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krek1111 [17]
3 years ago
13

What are the values of the missing forces?

Chemistry
1 answer:
bija089 [108]3 years ago
5 0
A: 12 N
B: 150 N
C: 100 N
D: 150 N
E: 220 N
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Suppose you had 2.0158 grams of (H2) how many moles of hydrogen do u have ?
ale4655 [162]
\hbox { You have to calculate the Molecular Mass for H2:}

M_{H2} = 2A _{H2} = 2*1=2 \hbox { grames/mole}

\hbox { So, in 2,0158 grames of H you will have 1 mole...}
7 0
3 years ago
The reaction below is at equilibrium. What would happen if more carbon were
schepotkina [342]

Explanation:

C_{(s)} + O_{2(g)} \rightleftharpoons CO_{2(g)}

<em>According to <u>le ch</u></em><em><u>-</u></em><em><u>atelier'</u></em><em><u>s</u></em><em><u> </u></em><em><u>principle</u> when a chemical reaction at equilibrium subjected to any stress, then the equilibrium shifts in that direction in which effect of stress is reduced.</em>

When we would add more number of carbon in above reaction then rate of forward reaction will increase to attain the equilibrium again.

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5 0
2 years ago
Non-renewable energy is often called?​
DIA [1.3K]

Answer:

It is also called a finite resource

Explanation:

5 0
3 years ago
What color does red litmus paper turn in an acid base and neutral solution?
quester [9]
<span> red litmus paper turns </span>blue <span>under basic or alkaline conditions, with the color change occurring over the pH range 4.5–8.3 at 25 °C (77 °F). Neutral litmus paper is purple.</span>
6 0
3 years ago
Read 2 more answers
The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate
Cloud [144]

Answer : The \Delta G for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,  

Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : Cu\rightarrow Cu^{2+}+2e^-

Reduction : 2Ag^++2e^-\rightarrow 2Ag

Now we have to calculate the Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole

Therefore, the \Delta G for this reaction is, -88780 J/mole.

7 0
3 years ago
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