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krek1111 [17]
3 years ago
13

What are the values of the missing forces?

Chemistry
1 answer:
bija089 [108]3 years ago
5 0
A: 12 N
B: 150 N
C: 100 N
D: 150 N
E: 220 N
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A solution contains 2.2 × 10-3 M in Cu2+ and 0.33 M in LiCN. If the Kf for Cu(CN)42- is 1.0 × 1025, how much copper ion remains
Taya2010 [7]

Answer:

[Cu²⁺] = 2.01x10⁻²⁶

Explanation:

The equilibrium of Cu(CN)₄²⁻ is:

Cu²⁺ + 4CN⁻ ⇄ Cu(CN)₄²⁻

And Kf is defined as:

Kf = 1.0x10²⁵ = [Cu(CN)₄²⁻] / [Cu²⁺] [CN⁻]⁴

As Kf is too high you can assume all Cu²⁺ is converted in Cu(CN)₄²⁻ -Cu²⁺ is limiting reactant-, the new concentrations will be:

[Cu²⁺] = 0

[CN⁻] = 0.33M - 4×2.2x10⁻³ = 0.3212M

[Cu(CN)₄²⁻] = 2.2x10⁻³

Some [Cu²⁺] will be formed and equilibrium concentrations will be:

[Cu²⁺] = X

[CN⁻] = 0.3212M + 4X

[Cu(CN)₄²⁻] = 2.2x10⁻³ - X

<em>Where X is reaction coordinate</em>

<em />

Replacing in Kf equation:

1.0x10²⁵ = [2.2x10⁻³ - X] / [X] [0.3212M +4X]⁴

1.0x10²⁵ = [2.2x10⁻³ - X] / 0.0104858X + 0.524288 X² + 9.8304 X³ + 81.92 X⁴ + 256 X⁵

1.04858x10²³X + 5.24288x10²⁴ X² + 9.8304x10²⁵ X³ + 8.192x10²⁶ X⁴ + 2.56x10²⁷ X⁵ = 2.2x10⁻³ - X

1.04858x10²³X + 5.24288x10²⁴ X² + 9.8304x10²⁵ X³ + 8.192x10²⁶ X⁴ + 2.56x10²⁷ X⁵ - 2.2x10⁻³ = 0

Solving for X:

X = 2.01x10⁻²⁶

As

[Cu²⁺] = X

<h3>[Cu²⁺] = 2.01x10⁻²⁶</h3>

5 0
3 years ago
When the name of a molecule ends in -ose, the molecule is a
Nonamiya [84]
It means that is it a sugar molecule
5 0
3 years ago
Read 2 more answers
Given the equation I = Q/t, solve for t.
larisa86 [58]

Answer: t=\frac{Q}{I}

Explanation:

I=\frac{Q}{t}

Multiply by t on both sides.

t*I=\frac{Q}{t}*t

tI=Q

Now divide by I to isolate t.

\frac{tI}{I}=\frac{Q}{I}

t=\frac{Q}{I}

5 0
3 years ago
How can the partial charges be shown in a polar covalent molecule?
joja [24]
Δ, namely δ− or δ+. Partial charges<span>are created due to the asymmetric distribution of electrons in chemical bonds. For example, in a </span>polar covalent<span> bond like HCl, the shared electron oscillates between the bonded atoms.</span>



Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
7 0
3 years ago
A 63 gram piece of magnesium absorbs 6689 joules of heat. The final temperature is 663 degrees Celsius. What was the initial tem
Gemiola [76]

Answer:

559^{\circ}C

Explanation:

When heat is supplied to a substance, the temperature of the substance increases according to:

Q=m C (T_f-T_i)

where

Q is the amount of heat supplied

m is the mass of the substance

C is the specific heat capacity of the substance

T_i is the initial temperature

T_f is the final temperature

For the sample of magnesium in this problem, we have:

m = 63 g is the mass

Q = 6689 J is the hear supplied

C = 1.023 J/gC is the specific heat capacity

T_f=663^{\circ}C is the final temperature

Solving the formula for T_i, we find the final temperature:

T_i = T_f-\frac{Q}{mC}=663-\frac{6689}{(63)(1.023)}=559^{\circ}C

6 0
3 years ago
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