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VladimirAG [237]
3 years ago
9

Alice added sodium chloride to water and stirred the water for several minutes. Alice is most likely trying to demonstrate that

ionic compounds 1. are hard 2. can dissolve 3. are clear 4. can melt
Chemistry
2 answers:
SashulF [63]3 years ago
6 0

Answer is: 2. can dissolve.

Ionic compounds separates into particles (ions) in water because of their ionic bond.

For example sodium chloride is ionic compound and strong electrolyte and dissociates in water on hydrated sodium cations and chlorine anions:

NaCl(aq) → Na⁺(aq) + Cl⁻(aq).

Ionic bond is the electrostatic attraction between oppositely charged ions (cations and anions).

djyliett [7]3 years ago
4 0
Can dissolve is the answer 
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The formula unit for beryllium oxide is BeO

Explanation:Mark me as brainliest

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3 years ago
Calculate the kilojoules needed to heat 231 g of gold from 18 ∘C to 195 ∘C.
LuckyWell [14K]

5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.

We have 231 g of gold at 18 °C and supply it with heat to increase its temperature to 195 °C. We can calculate the amount of heat required using the following expression.

Q = c \times m \times \Delta T

where,

  • Q: heat
  • <em>c: specific heat capacity of gold</em> (0.129 J/g.°C)
  • m: mass
  • ΔT: change in the temperature

Q = \frac{0.129 J}{g.\° C}  \times 231 g \times (195 \° C - 18 \° C) = 5.27 \times 10^{3} J = 5.27 kJ

5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.

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8 0
2 years ago
A 2-kg block rests on a wall that is 3 m tall. What is the gravitational potential energy of the block? The force of gravity on
Keith_Richards [23]
PE= weight x height. (remember weight is the force of gravity acting on objects...NOT the same as mass)

PE=3*2*9.8
PE=6*9.8
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7 0
3 years ago
Irony can be seen in which of the following lines? (Mark all that apply.)
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Awnser Is B

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What volume of a concentrated HCl solution, which is 36.0% HCl by mass and has a density of 1.179 g/mL, should be used to make 4
Ivenika [448]

Answer:

130ml of HCl(36%) in 4.90L solution => pH = 1.50

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Need 4.90L of HCl(aq) solution with pH = 1.5.

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=> V(conc) needed = [(0.032)(4.91)/12]Liters = 0.0130Liters or 130 ml.

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