Answer:
A). Calcium chloride dihydrate (CaCl2 * 2H2O) slowly heated in a crucible to become calcium chloride (anhydrous).
Dehyration is a physical process
B). A hydrocarbon such as propane (C3H8) undergoes combustion to power a grill
Combustion is a chemical process.
C). A rock climber’s rope becomes frayed and turns the color of the rocks
This is physical process
D). A dog urinates on an air conditioner coil and the coil becomes corroded
Corrsion is a chemical process.
Explanation:
Answer:
A
Explanation:
In a cold front set-up, the boundary between the cold and warm air masses is relatively steep, typically causing the warm air in front of it to rise rapidly.
In Fisher esterification, sulfuric acid is used as a catalyst and its function is to convert the carboxylic compound in its conjugate acid. This favours the nucleophilic attack of the alcohol. To act as a catalyst you need a strong acid, therefore sulphuric acid is suitable for this kind of reaction.
Answer:
Ⓓ The process follows the law of conservation of mass and energy is found in the product
Explanation:
This question depicts PHOTOSYNTHESIS, which is the process employed by green plants to manufacture their food in form of sugars (glucose). The general equation, which was given in the question is as follows:
6CO2 + 6H2O + energy → C6H12O6 + 6O2
This chemical reaction follows the LAW OF CONSERVATION OF MASS, which states that the amount of matter in reactant must equate that of the product. In this case, each element contains the same number of atoms in both reactant side and product side.
Also, energy is contained in the product but stored in the chemical bonds of the glucose molecule formed.
Hello!
When NaOH is added to a buffer composed of CH₃COOH and CH₃COO⁻, the following reactions happen:
-First, the NaOH is neutralized by CH₃COOH:
NaOH + CH₃COOH → H₂O + CH₃COONa
-Second, the CH₃COONa dissociates in its ions:
CH₃COONa → CH₃COO⁻ + Na⁺
-Finally, CH₃COO⁻ (a weak base) reacts with water to form OH⁻ ions and regenerate CH₃COOH
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻
By this sequence of reactions, the buffer can mitigate the effect of the strong base added.
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