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miv72 [106K]
4 years ago
12

Building up electric charges on a Van de Graaff generator is an example of static

Physics
2 answers:
KonstantinChe [14]4 years ago
8 0
Yes, this is true. Van de Graaff generators are devices that produce static this electricity right now.
sdas [7]4 years ago
5 0
Yes, that is true. Van de Graaff generators are devices that produce static electricity. Static does not involve acceleration, meaning it is motionless which applies to the building of electric charges since the building up of these electric charges are created in a way to not move. Therefore, the sentence you have stated is an accurate statement. 

Let me know if you need anything else. :)

               ~ Dotz
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If you start skating down this hill, your potential energy will be converted to kinetic energy. At the bottom of the hill, your
baherus [9]
Your potential energy at the top of the hill was (mass) x (gravity) x (height) .

Your kinetic energy at the bottom of the hill is (1/2) x (mass) x (speed)² .

If there was no loss of energy on the way down, then your kinetic energy
at the bottom will be equal to your potential energy at the top.

(1/2) x (mass) x (speed)² = (mass) x (gravity) x (height)

Divide each side by 'mass' :

(1/2) x (speed)² = (gravity) x (height) . . . The answer we get
will be the same for every skater, fat or skinny, heavy or light.
The skater's mass doesn't appear in the equation any more.

Multiply each side by 2 :

(speed)² = 2 x (gravity) x (height)

Take the square root of each side:

<u>Speed at the bottom = square root of(2 x gravity x height of the hill)</u>

We could go one step further, since we know the acceleration of gravity on Earth:

Speed at the bottom = 4.43 x square root of (height of the hill)

This is interesting, because it says that a hill twice as high won't give you
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6 0
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