1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Blababa [14]
3 years ago
6

You find a publication from a research laboratory that identifies a new catalyst for ammonia synthesis. The article contains the

following details about the process run in the author's lab:
The chemical reaction is N2 3H2 --> 2NH3
The reaction is exothermic
A fixed bed reactor is used with ruthenium catalyst on graphite support
The reactor is run at 430oC and 250 bar with space velocity of 8000 m3 m-3 h-1
At this temperature and pressure, the reactants and products are in the gas phase
The reactants are fed at flow rates of 400 lbmol/h H2 and 100 lbmol/h N2
The extent of reaction is 90 lbmol/h

You are considering replacing the current iron-oxide catalyst used in your ammonia synthesis plant with this newly discovered ruthenium-based catalyst. You plan to start your evaluation with a model in Aspen Plus and an economic analysis in APEA.

Based only on the information above from the literature, which project component would you select to map this reactor in APEA?
Engineering
1 answer:
Sidana [21]3 years ago
6 0

Answer:

Answer: RStoic

Explanation:

The reactor i will select to model this reactor in Aspenplus is RStoic

with the following reason;

Reason: Rstoic is used in Aspen software when the stoichiometry of reaction is known but kinetics isn't available. It can have one or more feed streams attached to it.

Reasons why other reactors are not preferred:

RYield: RYield performs the calculations based on the yield and we are not provided with the yield.

REquil: REquil is used when we are provided with stoichiometry of the reaction and information about equilibrium constant so that to perform chemical and phase equilibrium reactions & we are not provided with the equilibrium information.

RGibbs: Since reactor and products are in the gas phase, so it is not required to use it as it's used to minimise Gibbs free energy.

RCSTR: Reaction kinetics needed but we are not provided with it.

RPlug: Reaction kinetics needed but we are not provided with it.

RBatch: Reaction kinetics needed but we are not provided with it.

You might be interested in
Could I please get help with this​
alex41 [277]

Answer:

1.I_{xc} = 7.161458\overline 3 in.⁴

I_{yc} = 36.661458\overline 3 in.⁴

Iₓ = 28.6458\overline 3 in.⁴

I_y = 138.6548\overline 3 in.⁴

2. I_{xc} = 114.\overline 3 in.⁴

I_{yc} = 37.\overline 3 in.⁴

Iₓ = 457.\overline 3 in.⁴

I_y = 149.\overline 3 in.⁴

3. The maximum deflection of the beam is 2.55552 inches

Explanation:

1. The height of the beam having a rectangular cross section is h = 2.5 in.

The breadth of the beam, is = 5.5 in.

The moment of inertia of a rectangular beam through its centroid is given as follows;

I_{xc} = b·h³/12 = 5.5 × 2.5³/12 = 1375/192 = 7.161458\overline 3

I_{xc} = 7.161458\overline 3 in.⁴

I_{yc} = h·b³/12 = 2.5 × 5.5³/12 = 6655/192 = 36.661458\overline 3

I_{yc} = 36.661458\overline 3 in.⁴

The moment of inertia about the base is given as follows;

Iₓ = b·h³/3 = 5.5 × 2.5³/3 = 625/24 = 28.6458\overline 3

Iₓ = 28.6458\overline 3 in.⁴

I_y = h·b³/3 = 2.5 × 5.5³/3 = 6655/48= 138.6548\overline 3

I_y = 138.6548\overline 3 in.⁴

2. The height of the beam having a rectangular cross section is h = 7 in.

The breadth of the beam, b = 4 in.

The moment of inertia of a rectangular beam through its centroid is given as follows;

I_{xc} = b·h³/12 = 4 × 7³/12 = 114.\overline 3

I_{xc} = 114.\overline 3 in.⁴

I_{yc} = h·b³/12 = 7 × 4³/12 = 37.\overline 3

I_{yc} = 37.\overline 3 in.⁴

The moment of inertia about the base is given as follows;

Iₓ = b·h³/3 = 4 × 7³/3 = 457.\overline 3

Iₓ = 457.\overline 3 in.⁴

I_y = h·b³/3 = 2.5 × 5.5³/3 = 149.\overline 3

I_y = 149.\overline 3 in.⁴

3. The deflection, \delta _{max}, of a simply supported beam having a point load at the center is given as follows;

\delta_{max} = \dfrac{W \times L^3}{48 \times E \times I}

The given parameters of the beam are;

The length of the beam, L = 22 ft. = 264 in.

The applied load at the center, W = 750 lbs

The modulus of elasticity for Cedar = 10,000,000 psi

The height of the wood, h = 3 in.

The breadth of the wood, b = 5 in.

The moment of inertia of the wood, I_{xc} = b·h³/12 = 5 × 3³/12 = 11.25 in.⁴

By plugging in the given values, we have;

\delta_{max} = \dfrac{750 \times 264^3}{48 \times 10,000,000 \times 11.25} = 2.55552

The maximum deflection of the beam, \delta _{max} = 2.55552 inches

5 0
3 years ago
Is there a project idea, or invention that would be good for<br> my class.
Troyanec [42]

Answer:

Explanation:

A torch with an additional bulb. ...

Wheel chair convertible to crutches. ...

Pen to check concentration. ...

Bulb/CFL remover/connector. ...

Multicolor headphone wires. ...

Adjustable electricity extension board. ...

Automatic blade swinging ceiling fan for easy cleaning

3 0
2 years ago
Read 2 more answers
The rate at which velocity changes is called?
Travka [436]

The rate at which velocity changes is called acceleration

7 0
3 years ago
Read 2 more answers
Two variables, num_boys and num_girls, hold the number of boys and girls that have registered for an elementary school. The vari
Flauer [41]

Answer:

Using python

num_boys = int(input("Enter number of boys :"))

num_girls = int(input("Enter number of girls :"))

budget = int(input("Enter the number of dollars spent per school year :"))

try:

dollarperstudent = budget/(num_boys+num_girls)

print("Dollar spent per student : "+str(dollarperstudent))#final result

except ZeroDivisionError:

print("unavailable")

3 0
3 years ago
The section should span between 10.9 and 13.4 cm (4.30 and 5.30 inches) as measured from the end supports and should be able to
Sergeeva-Olga [200]

Answer:

hello below is missing piece of the complete question

minimum size = 0.3 cm

answer : 0.247 N/mm2

Explanation:

Given data :

section span : 10.9 and 13.4 cm

minimum load applied evenly to the top of span  : 13 N

maximum load for each member ; 4.5 N

lets take each member to be 4.2 cm

Determine the max value of P before truss fails

Taking average value of section span ≈ 12 cm

Given minimum load distributed evenly on top of section span = 13 N  

we will calculate the value of   by applying this formula

= \frac{Wl^2}{12}  =  (0.013 * 0.0144 )/ 12  =  1.56 * 10^-5

next we will consider section ; 4.2 cm * 0.3 cm

hence Z (section modulus ) = BD^2 / 6  

                                             = ( 0.042 * 0.003^2 ) / 6  = 6.3*10^-8

Finally the max value of P( stress ) before the truss fails

= M/Z = ( 1.56 * 10^-5 ) / ( 6.3*10^-8 )  

          = 0.247 N/mm2

5 0
2 years ago
Other questions:
  • The enthalpy of the water entering an actual pump is 500 kJ/kg and the enthalpy of the water leaving it is 550 kJ/kg. The pump h
    10·1 answer
  • How do batteries and other types of power sources make physical computing systems more mobile?
    15·2 answers
  • True or False:<br> Less than 2% of the U.S. population make their living producing food and fiber.
    13·1 answer
  • What kind or kinds of engineers does take to design a drone and why?
    11·1 answer
  • Give a reason why fighter aircraft use mid-wing design.
    11·1 answer
  • Which of the following is an example of a reliable source?
    10·1 answer
  • In dynamics, the friction force acting on a moving object is always a) in the same direction of its motion b) a kinetic friction
    15·1 answer
  • A 60-Hz 3-phase induction motor is required to drive a load at approximately 850 rpm. How many poles should the motor have
    9·1 answer
  • When you accelerate, the size of the front tire patch becomes____
    15·1 answer
  • HELP _7. All of the following except which would lead to an INCREASE in friction?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!