Military glorification through mosaics, relief carvings and triumphant arches are often associated with roman architectural monument and is the correct choice.
<h3>What is a Monument?</h3>
This can be defined as a structure which is usually large and is used to commemorate the history of an influential person. This helps to serve as an example and also a reminder as to why the performance of good deeds are important
The use of military glorification through mosaics, relief carvings and triumphant arches were also often used by the Romans in other to commemorate war victories and the succession of a new ruler which is known as the emperor.
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Most business owners begin his business in order to increase profit and to expand.
<h3>What are Business Practices?</h3>
This refers to the various ways in which a business owner decides to organize his business and the policies which guides it.
With this in mind, we can see that Mr X believes that it is a good business practice to <em>prioritize the work</em> that seems the most difficult and the most likely to kill their projects but this is not a good business practice because it can put the entire business in jeopardy.
Please note that your question is incomplete so I gave you a general overview so that you could get a better understanding of the concept.
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Answer:
8*10000+3*1000+1*00+2*10+2
Explanation:
Los sistemas de producción pecuaria, son considerados como la estrategia social, económica y cultural más apropiada para mantener el bienestar de las comunidades, debido a que es la única actividad que puede simultáneamente proveer seguridad en el sustento diario, conservar ecosistemas, promover la conservación de la
Answer:
Heat losses by convection, Qconv = 90W
Heat losses by radiation, Qrad = 5.814W
Explanation:
Heat transfer is defined as the transfer of heat from the heat surface to the object that needs to be heated. There are three types which are:
1. Radiation
2. Conduction
3. Convection
Convection is defined as the transfer of heat through the actual movement of the molecules.
Qconv = hA(Temp.final - Temp.surr)
Where h = 6.4KW/m2K
A, area of a square = L2
= (0.25)2
= 0.0625m2
Temp.final = 250°C
Temp.surr = 25°C
Q = 64 * 0.0625 * (250 - 25)
= 90W
Radiation is a heat transfer method that does not rely upon the contact between the initial heat source and the object to be heated, it can be called thermal radiation.
Qrad = E*S*(Temp.final4 - Temp.surr4)
Where E = emissivity of the surface
S = boltzmann constant
= 5.6703 x 10-8 W/m2K4
Qrad = 5.6703 x 10-8 * 0.42 * 0.0625 * ((250)4 - (25)4)
= 5.814 W
