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lisabon 2012 [21]
3 years ago
7

Velocity and acceleration are both vectors; they have a direction. What is thedirection of the velocity and acceleration vectors

of a tennis ball that is rising upward towards its highest point above the ground? a.The velocity vector is directed upward. b.The velocity vector is directed downward. c.The acceleration is directed downward. d.Both A & C
Physics
1 answer:
just olya [345]3 years ago
3 0

Answer:

d. Both A & C

Explanation:

- The velocity of the ball is a vector, whose magnitude indicates its rate of change of position, and it has a direction. In this case, the ball is moving upward, therefore the direction of motion is upward, so the direction of the velocity is upward as well.

- The acceleration of the ball is a vector, whose magnitude indicates the rate of change of the velocity. The direction of the acceleration is:

-- positive if the the magnitude of the velocity is increasing

-- negative if the magnitude of the velocity is decreasing

For a ball thrown upward, the acceleration is given by the acceleration of gravity, g=9.8 m/s^2. This acceleration points downward, and it is constant during the entire motion. In particular, it does not change direction, as it is always directed downward. Therefore, the acceleration of the ball is downward.

So, the correct answer is

d.Both A & C

Since A and C are both true:

a.The velocity vector is directed upward.

c.The acceleration is directed downward.

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The intensity of an earthquake wave passing through the earth is measured to be 2.5×106 j/(m2⋅s) at a distance of 43 km from the
vampirchik [111]

r₁ = distance of the point from the source = 43 km = 43000 m

I₁ = intensity of earthquake wave at distance "r₁" = 2.5 x 10⁶ W/m²

r₂ = distance of the point from the source = 1.5 km = 1500 m

I₂ = intensity of earthquake wave at distance "r₂" = ?

we know that , for a constant power , the intensity of wave is inversely proportional to the distance from the source .

I α 1/r²             where I = intensity of wave , r = distance from source

hence we can write

I₁/I₂ = r₂²/r₁²

inserting the values

(2.5 x 10⁶) /I₂ = (1500/43000)²

I₂ = 2.1 x 10⁹ W/m²

4 0
3 years ago
A curved road has a radius of 120 m and a cant angle of 48 degrees. What is the maximum speed to stay on the curve in the absenc
zalisa [80]

Answer:

Maximum speed, v = 36 m/s                                                          

Explanation:

Given that,

The radius of the curved road, r = 120 m

Road is at an angle of 48 degrees. We need to find the maximum speed of stay on the curve in the absence of friction. On a banked curve, the angle at which it is cant is given by :

tan\theta=\dfrac{v^2}{rg}

g is the acceleration due to gravity  

v=\sqrt{rg\ tan\theta}

v=\sqrt{120\times 9.8\times \ tan(48)}

v = 36.13 m/s

or

v = 36 m/s

So, the maximum speed to stay on the curve in the absence of friction is 36 m/s. Hence, this is the required solution.

7 0
3 years ago
Mass and weight are the same in<br> meaning and unit.<br><br> true or false
schepotkina [342]

Answer:

False.

Explanation:

Mass is how much space an object takes up, while weight is how light or heavy an object is.

4 0
3 years ago
Imagine that you are in a bleachers watching a swim meet in which your friend is competing in the freestyle event. At the instan
kramer

The two possible distances that you might infer your friends swam while the lights were out are 25 m and 75 m.

Answer:

Explanation:

So you have to measure the distance covered by your friend in a time gap of 86 s. And the average velocity is given as 0.29 m/s.

Then as per the mathematical calculation of velocity, distance can be measured as the product of velocity with time interval.

Distance = Velocity × Time Interval

Distance = 0.29 m/s×86 s = 24.94 m.

So based on this calculation, one of the possible distance inferred by you will be 24.94 m.

Another possible distance can be guessed from the statements provided. So if the length of pool is 50 m, then covering halfway in opposite direction to his starting direction means completion of one full length i.e., 50 m and then halfway of that 50 m which is 25m, so totally 50 +25 = 75 m.

So in other way, we can assume that your friend has covered 75 m distance during the light out.

Thus, the two possible distances that you might infer your friends swam while the lights were out are 25 m and 75 m.

7 0
3 years ago
Please answer this fast <br>I 'll marks them brainliest answer <br>​
Reptile [31]

answer

64 is C (c) 1-Bromo-3-methylbutane

63 is D

i is secondary ii is primary

8 0
2 years ago
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