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Advocard [28]
3 years ago
7

HELP ASAPP!!!! WILL GIVE BRAINLIEST! Describe the chemical structure of a cell membrane

Physics
2 answers:
Masja [62]3 years ago
5 0

Answer:

Explanation:

The plasma membrane is composed of a bilayer of phospholipids, with their hydrophobic, fatty acid tails in contact with each other. ... Carbohydrates are attached to some of the proteins and lipids on the outward-facing surface of the membrane. These form complexes that function to identify the cell to other cells.

Andrei [34K]3 years ago
4 0

Answer is:

The plasma membrane is composed of a bilayer of phospholipids, with their hydrophobic, fatty acid tails in contact with each other. ... Carbohydrates are attached to some of the proteins and lipids on the outward-facing surface of the membrane. These form complexes that function to identify the cell to other cells.

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Stels [109]

Answer:

u right u right, curious what color shade that is

8 0
3 years ago
Read 2 more answers
Planet x has a mass of 4x1022 kg and a radius of 6x105 m What lise the grav ritational field strength in the surface of planet X
SCORPION-xisa [38]

Answer:

  g ≈ 7.4 m/s²

Explanation:

The acceleration due to gravity on planet XX is ...

  g = GM/r² = (6.67·10^-11 × 4·10^22)/(6·10^5)^2

  g ≈ 7.4 m/s²

6 0
3 years ago
A car traveling 75 km/h slows down at a constant 0.50 m/s2 just by "letting up on the gas." calculate (a) the distance the car c
Serjik [45]

Solution:

At 1st convert km/h to m/s. 1 km = 1000 m, 1 h = 3600 s, 1 km/m = 1000/3600 = 5/18 m/s  

Initial velocity = 75 * 5/18 = 20.8 m/s  

The car’s velocity decreases from 20.8 m/s to 0 m/s at the rate of 0.5 m/s each second. We have the final velocity, initial velocity, and the acceleration.  

Now according to the equation determine the distance.  

vf^2 = vi^2 + 2 * a * d  

a = -0.5 m/s^2  

0 = 20.8^2 + 2 * -0.5 * d  

so d = 431.64 m  

since we have the final velocity, initial velocity, and the acceleration. Use the following equation to determine time.  

vf = vi + a * t  

0 = 20.8 – 0.5 * t  

Solve for t = 41 seconds  

(c) the distance travels by it during the first and fifth second are.  

d = vi * t + ½ * a * t^2  

d1 = 20.8 * 1 – ½ * 0.5 * 1^2 = 20.55 m  

The easiest way to the distance for the 5th second is:

d = vi * t + ½ * a * t^2, a = -0.5  

d5 = 20.8 * 5 – ½ * 0.5 * 5^2 = 91.5 m  

d6 = 20.8 * 6 – ½ * 0.5 * 6^2 =  106.8m

d6 – d5 = 15.3 m  

this is the required solution.


3 0
3 years ago
True or false: When an object becomes polarized, it acquires a charge and becomes a charged object.​
PSYCHO15rus [73]

Answer:

i think its true

Explanation:

8 0
3 years ago
What is the internal resistance of a 12.0 V car battery whose terminal voltage drops to 8.2 V when the starter draws 75 A
jonny [76]

Answer:

The internal resistance of the cell is 0.051 ohm.

Explanation:

Given;

emf of the battery, E = 12 V

terminal voltage of the cell, V = 8.2 V

current in the circuit, I = 75 A

let the potential drop of the cell due to internal resistance (r) = Ir

The internal resistance of the cell is calculated from the equation below;

E = V + Ir

where;

r is the internal resistance of the cell

Ir = E - V\\\\r = \frac{E-V}{I} \\\\r = \frac{12-8.2}{75} \\\\r = 0.051 \ ohm

Therefore, the internal resistance of the cell is 0.051 ohm.

6 0
3 years ago
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