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2 years ago

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By the 2nd century BCE the ____ democratized astrology A. Greeks B. Egyptians C. Romans

1 answer:

elena-14-01-66 [18.8K]2 years ago

3 0

Answer:

A

Explanation:

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25.16 what is the reaction product of acetic acid and ethylamine at room temperature?

Ne4ueva [31]

The ammonium salt of acetic acid is the reaction product of acetic acid and ethylamine at room temperature

<h3 /><h3>What is acetic acid ?</h3>

Acetic acid is a monofunctional carboxylic acid containing two carbon atoms. It acts as a protein solvent, food acidity regulator, antibacterial food preservative. It is a conjugate acid of an acetate.

Acetic acid is used in the production of acetic anhydride, cellulose acetate, vinyl acetate monomer, acetic ester, chloroacetic acid, plastics, dyes, insecticides, photographic chemicals, and rubber. Other commercial uses include the production of vitamins, antibiotics, hormones, organic chemicals, and as a food additive. Typical concentrations of acetic acid found naturally in foods are 700 to 1200 milligrams/kg (mg/kg) in wine, up to 860 mg/kg in aged cheeses, and 2.8 mg/kg in aged cheeses. fresh orange juice.

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3 months ago

What does the word “adverse” mean in the following sentence? Adverse reactions, such as fever and headache, can occur if the med

Stells [14]

I think it's D. unfavorable hope it helps

3 0

2 years ago

Read 2 more answers

A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is

Tanya [424]

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with <u>uniform circular motion</u>, her centripetal acceleration $a_{c}$ is given by the following equation:

$a_{c}=\frac{V^{2}}{r}$ (1)

Where:

$a_{c}=17 m/s^{2}$ is the <u>centripetal acceleration</u>

$V$ is the<u> tangential speed</u>

$r=12 m$ is the <u>radius</u> of the circle

Isolating $V$ from (1):

$V=\sqrt{a_{c}r}$ (2)

$V=\sqrt{(17 m/s^{2})(12 m)}$

<u />

Finally:

$V=14.28 m/s$ This is the girl's tangential speed

3 0

2 years ago

A. Group of cross country runners decided to go on an hour and a half run. During the first hour, they ran a total of 13 kilomet

pshichka [43]

Answer:

The average speed for the entire run is 12 km/h.

Explanation:

The average speed is given by the following equation:

$\overline{v} = \frac{d_{T}}{t_{T}}$

Where:

$d_{T}$ : is the total distance

$t_{T}$ : is the total time

If during the first hour, they ran a total of 13 kilometers and then, they ran 5.0 kilometers during the next half an hour we have:

$d_{T} = 13 km + 5 km = 18 km$

$t_{T} = 1 h + \frac{1}{2} h = 1.5 h$

Hence, the average speed is:

$\overline{v} = \frac{d_{T}}{t_{T}} = \frac{18 km}{1.5 h} = 12 km/h$

Therefore, the average speed for the entire run is 12 km/h.

I hope it helps you!

3 0

2 years ago

Once Kate's kite reaches a height of 50 ft (above her hands), it rises no higher but drifts due east in a wind blowing 7 ft d

Margaret [11]

Answer:

dz = 7.136 (answer)

Explanation:

given height for kate's kite = 50 ft (say y)

due to drift it move towards east = dx = 7 ft

string maximum length = 107 ft ( say z)

we have to find change in z

that is dz

it will form a right angle triangle for x , y and z where x is base y is height and z is hypotenuse

so we get according to Pythagoras Theorem

$z^2 = x^2+y^2\\$ ...............(i)

by derivative both side consider y as constant

$2zdz = 2xdx\\dz = {xdx }/z$

from (i) equation

$x = \sqrt{z^2-y^2}$

$dz = \sqrt{z^2-y^2}dx/z$

now put the value and find dz

$dz = (\sqrt{120^2-50^2)}7/107\\ =((\sqrt{14400 -2500} )\times7)/107$

after solving these we get

$dz =\frac{109.08\times7}{107}$

dz = 7.136 (answer)

7 0

2 years ago