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Alla [95]
3 years ago
5

By the 2nd century BCE the ____ democratized astrology A. Greeks B. Egyptians C. Romans

Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

A

Explanation:

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A 920-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked,
GrogVix [38]

Answer:21.45 m/s

Explanation:

Given

Mass of sport car=920 kg

Mass of SUV=2300 kg

distance to which both car skid is 2.4 m

coefficient of friction (\mu)=0.8

Let u be the initial velocity of both car at the starting of skidding

and they finally come to zero velocity

v^2-u^2=2as

acceleration=\mu g=0.8\times 9.8=7.84 m/s^2

s=2.4 m

0-(u)^2=2\times (-7.84)\times 2.4

u=6.13 m/s

so before colliding sport car must be travelling at a speed of

920\times v=(920+2300)\times 6.13  (conserving momentum)

v=21.45 m/s

7 0
3 years ago
GIVING BRAINLIEST PLEASE HELP!!
erik [133]

Explanation:

the other 40% is used to power the 60% making it only capable of 60% efficiency

4 0
2 years ago
Seafloor spreading is a process that occurs along ___________1____________. At ___________2____________ boundary, two plates mov
sergejj [24]

Answer:

where is the answer choices

Explanation:

5 0
2 years ago
A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplit
likoan [24]

Answer:

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Explanation:

We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg

Length of wire l = 84 cm = 0.84 m

So mass density \mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m

Tension in the wire T = 25 N

Frequency f = 120 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 120=753.6rad/sec

And amplitude A = 1.6 mm = 0.0016 m

We have to find the generated power

Power is given by P=\frac{1}{2}\sqrt{\mu T}\omega ^2A^2=\frac{1}{2}\times \sqrt{0.0031\times 25}\times 753.6^2\times 0.0016^2=0.2023watt

From the relation we can see that power P\ \propto\ A^2

So if amplitude is halved then power will be \frac{1}{4} times

So power will be equal to \frac{0.2023}{2}=0.0505watt

4 0
3 years ago
Which of the following statement is not true about machines?
viva [34]
The answer to this question is D or the last one 

4 0
3 years ago
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