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Irina18 [472]
3 years ago
13

Jamie is a hairstylist who works in a salon. He noticed that when many of the stylist or blow drying hair the power goes out wha

t is the best scientific question that can be asked about Jamie's observations
Physics
2 answers:
Mashcka [7]3 years ago
6 0
The people are using a lot of electricity blow drying to many peoples hair so i would make a schedule so it dosent get to busy with costumers
tangare [24]3 years ago
3 0
With all the hairdryers on at the same time, there's a lot of current being drawn from the mains to supply the dryers. This has overloaded a circuit breaker/fuse somehwere in his system causing a power cut or safety reasons. He probably needs to get a qualified electrician in and get the wiring sorted out so that it can handle the electric current at peak demand, or schedule the demand so that the overload doesn't happen. If he's busy, then I'd go or the electrician option to keep things moving safely.
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Which technique is best for manual in-line stabilization of a person floating faceup on the surface?
zmey [24]

Answer:

vise grip

Explanation:

Manual in-line stabilization (MILS) of the cervical spine is a type of airway management when dealing with  patients in traumatic condition ..it is a means that is performed by grasping the mastoid process of the patient, so as to prevent the movement of the cervical column during intubation of the trachea

MLS provides a means of stability to the cervical column for a patient in trauma. During this technique, a patient is restricted from moving his or her cervical collar. The vise grip can be used for a patient with neck injury. The technique is used to roll a patient to face up to prevent further injuries.

7 0
2 years ago
Read 2 more answers
A cart of mass m = 0.12 kg moves with a speed v = 0.45 m/s on a frictionless air track and collides with an identical cart that
lina2011 [118]

Answer:

0.006075Joules

Explanation:

The final kinetic energy of the system is expressed as;

KE = 1/2(m1+m2)v²

m1 and m2 are the masses of the two bodies

v is the final velocity of the bodies after collision

get the final velocity using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

0.12(0.45) + 0/12(0) = (0.12+0.12)v

0.054 = 0.24v

v = 0.054/0.24

v = 0.225m/s

Get the final kinetic energy;

KE = 1/2(m1+m2)v

KE = 1/2(0.12+0.12)(0.225)²

KE = 1/2(0.24)(0.050625)

KE = 0.12*0.050625

KE = 0.006075Joules

Hence the final kinetic energy of the system is 0.006075Joules

5 0
2 years ago
Gauss’ law: a. Relates the surface charge density to the electric field.b. Relates the electric field at points on a closed surf
Mamont248 [21]

Answer:

b. Relates the electric field at points on a closed surface to the net charge enclosed by that surface

Explanation:

Gauss's law states that the flux of certain fields through a closed surface is proportional to the magnitude of the sources of that field within the same surface. The electric flux expresses the measure of the electric field that crosses a certain surface. Therefore, the electric field on a closed surface is proportional to the net charge enclosed by that surface.

8 0
3 years ago
Makenna surveyed 48 of her female classmates to determine the number of stores each one visited before purchasing a dress for th
Maslowich

48/4 = 12

the answer is 12


6 0
3 years ago
Read 2 more answers
A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
aliina [53]

Answer:

9.43 m/s

Explanation:

First of all, we calculate the final kinetic energy of the car.

According to the work-energy theorem, the work done on the car is equal to its change in kinetic energy:

W=K_f - K_i

where

W = -36.733 J is the work done on the car (negative because the car is slowing down, so the work is done in the direction opposite to the motion of the car)

K_f is the final kinetic energy

K_i = 66,120 J is the initial kinetic energy

Solving,

K_f = K_i + W = 66,120 + (-36,733)=29,387 J

Now we can find the final speed of the car by using the formula for kinetic energy

K_f = \frac{1}{2}mv^2

where

m = 661 kg is the mass of the car

v is its final speed

Solving for v, we find

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.43 m/s

3 0
3 years ago
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