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Irina18 [472]
3 years ago
13

Jamie is a hairstylist who works in a salon. He noticed that when many of the stylist or blow drying hair the power goes out wha

t is the best scientific question that can be asked about Jamie's observations
Physics
2 answers:
Mashcka [7]3 years ago
6 0
The people are using a lot of electricity blow drying to many peoples hair so i would make a schedule so it dosent get to busy with costumers
tangare [24]3 years ago
3 0
With all the hairdryers on at the same time, there's a lot of current being drawn from the mains to supply the dryers. This has overloaded a circuit breaker/fuse somehwere in his system causing a power cut or safety reasons. He probably needs to get a qualified electrician in and get the wiring sorted out so that it can handle the electric current at peak demand, or schedule the demand so that the overload doesn't happen. If he's busy, then I'd go or the electrician option to keep things moving safely.
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A 71 kW radio station broadcasts its signal uniformly in all directions. - What is the average intensity of its signal at a dist
marshall27 [118]

Answer:

Explanation:

Energy of signal being radiated per second on all sides = 71 x 10³ J .

At a distance of 220 m it is spread over an area of 4 π x (220)² because it is spreading uniformly on all sides.

So energy crossing per unit area

= \frac{71\times10^3}{4 \times \pi\times(220)^2}

= 11.67 x 10⁻² Wm⁻²s⁻¹.

This is the intensity of the signal.

At 2200 m this intensity will further reduce by 100 times

So there it becomes equal to

11.67 x 10⁻⁴ Wm⁻² s⁻¹.

3 0
3 years ago
The object of badminton is to hit the birdie or "shuttlecock" over the net and onto to court to score how many points to win gam
xxTIMURxx [149]

Answer:

either 7 or 21

Explanation:

6 0
3 years ago
Both objects A and D represent fixed, negatively-charged particles of equal magnitude and Object B represents a fixed, positivel
Kipish [7]

Answer:

Option A = 1.

Explanation:

So, in order to solve this question we are given the Important infomation or data or parameters in the question above as;

(1). First, Both objects A and D represent fixed.

(2).  Both objects A and D are negatively-charged particles of equal magnitude.

(3). "Object B represents a fixed, positively-charged particle (equal, but opposite charge from A and D)."

(4). "Object C shows a moving, positively-charged particle."

So, our mission is to determine the arrow that would correctly show the force of attraction or repulsion on object C caused by the other two objects.

We can do that by drawing out the forces of attraction and the resultants. Therefore, CHECK THE ATTACHED FILE/PICTURE FOR THE DRAWINGS.

The forces of attraction due to objects A and B on on object C will be towards themselves. Hence, the resultant is ONE(1).

6 0
3 years ago
A sound wave is direct at a wall. In 20 seconds, 200 wave cycles hit the wall.
Tems11 [23]

Answer:

Frequency=10 Hz

Period=0.1 s

Explanation:

Frequency of a wave is the number of complete cycles per unit time. Usually, frequency is cycles per second, with unit as Heartz

Given cycles of the wave as 200 and time as 20 seconds

Frequency=200÷20=10 cycles per second

Therefore, frequency is 10 Hz

Period is usually the reviprocal of frequency hence reciprocal of 10 Hz will be 1/10=0.1 s

7 0
3 years ago
You are standing on a sidewalk. There is a car in the distance. The horn on the car sounds. You hear it at a pitch that correspo
AnnyKZ [126]

Answer: The answer: The car is moving away from you.

Both A and C are true as Car can be moving in line away from you or has component of velocity in opposite direction.

Explanation:The decrease in the frequency of the sound is the result of Doppler's effect. A/c to Doppler's effect the frequency of received sound of source is changed if it is moving relative to the receiver, i.e. the distance between them is changing due to motion.

The general formula of Doppler's Effect is attached as the picture.

In this formula v_D is the velocity of Detector i.e the receiver relative to wind. While v_s is the velocity of source relative to wind and v is the velocity of sound.

The Doppler's effect is not effected by the velocity of wind as the wind itself could not change the distance between the two objects i.e. you and the car. Wind velocity can change the speed of sound and its wavelength but the change does not effect the frequency.

Hence if we assume the car to be moving with velocity v_c and you are stationary

f'=f_s*\frac{v}{v-v_c}

hence the frequency is reduced.

4 0
3 years ago
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