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ikadub [295]
3 years ago
14

If a charged particle is travelling in a helical shape as it moves through a magnetic field, but then the particle gains the opp

osite charge, what happens to it's travelling path? (1 point) The path remains helical, but it reverses in direction The path changes from helical to a spherical shape The path changes from helical to a triangular shape Nothing happens
Physics
2 answers:
Anarel [89]3 years ago
7 0

Answer:

Explanation:

The path of the charged particle is helical when it moves in a magnetic field and the particle enters at some arbitrary angle.

When the sign of the charged particle is changed, so the path remain helical but the direction of motion is reversed.

arsen [322]3 years ago
5 0

Answer:

I think it's "The path remains helical, but it reverses in direction"

Explanation:

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Both speed and velocity measure how fast something is moving. Hence, since speed is not a vector it does not require direction.

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4 years ago
A traveling electromagnetic wave in a vacuum has an electric field amplitude of 93.3 V/m. Calculate the intensity S of this wave
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Answer:

Intensity = 11.56W/m²

The energy flowing through the given area is 4.55 J

Explanation:

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I = \frac{1}{2} C{ {\varepsilon _0}E_m^2

Here,\varepsilon _0 is the permittivity of the free space,

E_m  is the electric field amplitude and

c is the speed of the light.

substitute

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8.85×10  −12  C² /N⋅m² for {\varepsilon _0}

and 93.3 V/m for {E_{\rm{m}

I = \frac{1}{2} \times (3\times10^8)\times(8.85\times10^-^1^2)(93.3)\\\\I = 11.56W/m^2

The expression for the energy is,

E = I×A×t

Here, I is the intensity of the electromagnetic wave,

A is the area, and

t is the time.

Substitute

11.56W/m² for I

0.0287m ² for A

13.7s for t

E = (11.56)\times(0,0287)\times(13.7)\\E = 4.55J

The energy flowing through the given area is 4.55 J

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4 years ago
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Answer:

The speed of bullet and wooden bock coupled together, V = 22.22 m/s

Explanation:

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Mass of the wooden block, M = 0.5 Kg

The initial velocity of the bullet, u = 300 m/s

The initial velocity of the wooden block, U = 0 m/s

The final velocity of the bullet and wooden bock coupled together, V = 0 m/s

According to the conservation of linear momentum, the total momentum of the body after impact is equal to the total momentum before impact.

Therefore,

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Substituting the values in the above equation,

                                V = 0.04 Kg x 300 m/s  / (0.04 Kg+ 0.5 Kg)

                                    = 22.22 m/s

Hence, the speed of bullet and wooden bock coupled together, V = 22.22 m/s

8 0
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