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3 years ago

Choose the correct converse.

Mathematics

2 answers:

irinina [24]3 years ago

8 0

Cccccccccccccccccccc

a_sh-v [17]3 years ago

6 0

Answer:

i think it is B i am not sure

Step-by-step explanation:

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Find an equation for the line that passes through the points (-5, -5) and (3, 5)

Luda [366]

Answer:

5x-4y+5=0.

Step-by-step explanation:

1) if the point A(-5;-5) and B(3;5), the formula is:

$\frac{x-X_A}{X_B-X_A} =\frac{y-Y_A}{Y_B-Y_A}$

2) according to the formula above:
$\frac{x+5}{3+5} =\frac{y+5}{5+5}; \ = > \ \frac{x+5}{4}=\frac{y+5}{5};$

or 5x-4y+5=0.

8 0

3 years ago

Solve the equation.<br><br> <img src="https://tex.z-dn.net/?f=w%2F3%20%3D%20-9" id="TexFormula1" title="w/3 = -9" alt="w/3 = -9"

kvasek [131]

Answer:

w= -27

Step-by-step explanation:

w/3 = -9

w = 3 * -9 = -27

7 0

3 years ago

HELP PLS I DONT KNOW THIS ONE

inessss [21]

Answer:

-------------

(x+2)(x-4)

Step-by-step explanation:

x+4 x+3

------------- * --------------

x^2+5x+6 x^2 -16

Factor

x+4 x+3

------------- * --------------

(x+3)(x+2) (x+4)(x-4)

Cancel like terms

1 1

------------- * --------------

(1)(x+2) (1)(x-4)

------------- x cannot equal -3, -4, -2, 4

(x+2)(x-4)

5 0

3 years ago

An organic farm has been growing an heirloom variety of summer squash. A sample of the weights of 40 summer squash revealed that

natta225 [31]

Answer:

b. 0.0228

Step-by-step explanation:

We are given that

n=40

Mean, $\mu=402.7 g$

Standard deviation, $\sigma=8.8$ g

We have to find the probability hat the mean weight for a sample of 40 summer squash exceeds 405.5 grams.

$P(x>405.5)=P(\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}>\frac{405.5-402.7}{\frac{8.8}{\sqrt{40}}})$

$P(x>405.5)=P(Z>\frac{2.8}{\frac{8.8}{\sqrt{40}}})$

$P(x>405.5)=P(Z>2.01)$

$P(x>405.5)=1-P(Z\leq 2.01)$

$P(x>405.5)=1-0.977784$

$P(x>405.5)=0.022216$

Hence, option b is correct.

5 0

3 years ago

The area of sector A08 is 48x and m<AOB = 270º. Find the radius of circle O.

Softa [21]

Answer:

Step-by-step explanation:

The first one gives us everything we need except the radius, which is easy enough to solve for if you're careful with your algebra. The area of a sector of a circle is given as:

$A_s=\frac{\theta}{360}*\pi r^2$ where θ is the measure of the central angle of the circle. For us, that fills in as follows:

$48\pi=\frac{270}{360}*\pi r^2$ and manipulate it as follows:

$r^2=\frac{(360)(48\pi)}{270\pi}$ the π's cancel out, leaving us with simple multiplication and division to get

r = 8. Now for the next one, which is a bit more involved.

In order to find the area of the shaded part, we need to find the area of the right triangle there and subtract it from the area of the sector of the circle. First the area of the sector, which is given as:

$A_s=\frac{\theta}{360}*\pi r^2$ where θ again is the measure of the central angle of the circle, 90°:

$A_s=\frac{90}{360}(3.1415)(10)^2$ which simplifies a bit to

$A_s=\frac{1}{4}(3.1415)(100)$ , giving us an area of

$A_s=78.5375m^2$ . Now onto the area of the triangle.

Since this triangle is inscribed in the circle and the circle's radius is 10, tha also gives us both the height and the base measures of the triangle. The area then is:

$A_t=\frac{1}{2}(10)(10)$ which is

$A_t=50m^2$

Subtract that from the area of the sector to get that the shaded area is 28.5 square meters, choice A.

4 0

3 years ago