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3 years ago

Stars are formed in which of the following?

Physics

1 answer:

MAXImum [283]3 years ago

6 0

Stars are formed in <u>nebulas</u>, interstellar clouds of dust and gas.

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An object with a mass of 5.0 kg accelerates 2.8 m/s2 towards right when an unknown force is applied to it. What is the amount of

RoseWind [281]

Answer:

Explanation:

5 0

3 years ago

A planet exerts a gravitational force of magnitude 9e22 N on a star. If the planet were 2 times closer to the star (that is, if

Dmitrij [34]

To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.

Planet gravitational force

$F_p = 6*10^{22}N$

$F_p = \frac{GMm}{R^2}$

$F_p = 9*10^{22}N$

Distance between planet and star

$r = \frac{R}{2}$

Gravitational force is

$F = \frac{GMm}{r^2}$

Applying the new distance,

$F = \frac{GMm}{(\frac{R}{2})^2}$

$F = 4\frac{GMm}{R^2}$

Replacing with the previous force,

$F = 4F_p$

Replacing our values

$F= 4(9*10^{22}N)$

$F = 36*10^{22}N$

Therefore the magnitude of the force on the star due to the planet is $36*10^{22}N$

5 0

3 years ago

What is the acceleration of a boy on a skateboard if the net force on the boy is 15 N? The total mass of the boy and the skatebo

Stels [109]

   Force = (mass) x (acceleration)

If the full 15N is pointing parallel to the ground,
then

   15 N = (58 kg) x (acceleration).

Divide each side
by 58 kg: Acceleration = 15 N / 58 kg

   = (15 kg-m/s²) / (58 kg)

   = (15/58) (kg-m/kg-s²)

   = 0.26 m/s² .

7 0

3 years ago

Read 2 more answers

A light spring of constant 176 N/m rests vertically on the bottom of a large beaker of water.

irakobra [83]

Answer:

14.0 cm

Explanation:

Draw a free body diagram of the block. There are three forces: weight force mg pulling down, elastic force k∆L pulling down, and buoyancy ρVg pushing up.

Sum of forces in the y direction:

∑F = ma

ρVg − mg − k∆L = 0

(1000 kg/m³) (4.63 kg / 648 kg/m³) (9.8 m/s²) − (4.63 kg) (9.8 m/s²) − (176 N/m) ∆L = 0

∆L = 0.140 m

∆L = 14.0 cm

8 0

3 years ago

8. Express 2.69 x 10^9 in standard form.

taurus [48]

Answer:

242.1

Explanation:

10 x 9 equals 90

2.69 x 90 = 242.1

5 0

3 years ago