Answer:
Explanation:
Applying conservation of momentum
mA v0 + 0 = mA x 12v0 + mB x 92v0
11 mA = - 92mB .
mA / mB = 92 / 11
mA : mB = 92 : 11.
Answer:
Energy of scattered photon is 232.27 keV.
Kinetic energy of recoil electron is 497.73 keV.
The recoil angle of electron is 13.40°
Explanation:
The energy of scattered photon is given by the relation :
.....(1)
Here E₁ is the energy of incident photon, E₂ is the energy of scattered photon,
is mass of electron and θ is scattered angle.
Substitute 730 keV for E₁, 511 keV for
and 120° for θ in equation (1).

E₂ = 232.27 keV
Kinetic energy of recoil electron is given by the relation :
K.E. = E₁ - E₂ = (730 - 232.27 ) keV = 497.73 keV
The recoil angle of electron is given by :

Substitute the suitable values in above equation.


= 13.40°
When gas hydrates are brought to the surface, they evaporate quickly. This would be the biggest, current disadvantage to using gas hydrates as a form of energy.
Answer:

Explanation:
As we know by the law of diffraction through circular aperture

here we know that
a = diameter of the aperture
= diffraction angle
= wavelength
now we have

Now in order to find the wavelength we know



now we have


