Answer:
Router
Explanation:
Routers have something called a WAN link, which can be used to connect 2 local area networks
Answer:
Program approach:-
- Using the header file.
- Using the standard namespace I/O.
- Define the main function.
- Display the number of terms.
- Display the Fibonacci series.
- Print the first two numbers.
Explanation:
Program:-
//header file
#include <iostream>
//using namespace
using namespace std;
//main function
int main() {
int n, s1 = 0, s2 = 1, nextTerm = 0;
//display the number of terms
cout << "Enter the number of terms: ";
cin >> n;
//display the Fibonacci series
cout << "Fibonacci Series: ";
for (int j = 1; j <= n; ++j) {
// Prints the first two terms.
if(j == 1) {
cout << s1 << ", ";
continue;
}
if(j == 2) {
cout << s2 << ", ";
continue;
}
nextTerm = s1 + s2;
s1 = s2;
s2 = nextTerm;
cout << nextTerm << ", ";
}
Answer:
a
Explanation:
System restoration and it is a tool to return the status of the system to a selected point previously created by the user or by the machine after installing a software or an important event.
Driving and driving, texting and driving, and teens that might not be able to hear or see at the best of their ability. Hope this helps :D
Answer:
Follows are the code to this question:
#include <iostream>//header file
using namespace std;
int main() //defining main method
{
int userNum, divNum;//defining integer variable
cin>> userNum >> divNum;//input values
cout <<"First-time divide: "<<userNum / divNum<<endl;//divide value First time
cout <<"Second-time divide: " << userNum / divNum/divNum<<endl; //divide value Second time
cout<<"Third-time divide: "<< userNum /divNum/divNum/divNum<<endl;//divide value Third time
return 0;
}
Output:
2000
2
First-time divide: 1000
Second-time divide: 500
Third-time divide: 250
Explanation:
In this code two integer variable "userNum and divNum" is declared that uses the input method to input value from the user-end, and after input the value it divides the "userNum by divNum" three times, that is defined as follows:
In this code, the user input the value 2000 and 2, in the first divides it will give 1000, in the second time divide it will give 500, and in the third time it will give 250.
