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earnstyle [38]
3 years ago
13

2-methylbut-2-ene react with chlorine gas​

Chemistry
2 answers:
Vitek1552 [10]3 years ago
3 0

Answer:

Ez 170

Explanation:

harkovskaia [24]3 years ago
3 0

Molecular Formula C5H10

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cricket20 [7]
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2 years ago
Describe briefly how to obtain the radial probability of an electron​
Kaylis [27]

Explanation:

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8 0
3 years ago
Suppose 2.8 moles of methane are allowed to react with 5 moles of oxygen.
Ronch [10]

Answer : The limiting reagent is O_2

Solution : Given,

Moles of methane = 2.8 moles

Moles of O_2 = 5 moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 5 moles of O_2 react with \frac{5}{2}=2.5 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Hence, the limiting reagent is O_2

8 0
4 years ago
How many milliliters of a 3.0 M HCL solution are required to make 250.0 millimeters of 1.2 M HCL?
White raven [17]
The problem above can be solved using M1V1=M2V2  where M1 is the concentration of the concentrated, V1 is the volume of the concentrated solution, M2 is the concentration of the Dilute Solution, V2 is the Volume of the dilute solution. Hence,

(3.0 M)(V2)=(250 mL)(1.2M)
V2 (3.0)= 300
V2= 100 mL

Therefore, you need 100 mL of 3.0 M HCl to form a 250 mL of 1.2 M HCl.
7 0
3 years ago
You plug in an extension cord and have to be very careful around the electrical outlet. However, you can handle the extension co
evablogger [386]
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3 years ago
Read 2 more answers
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