Answer:
3550ppm
<h3>explanation</h3>
A 1 M solution of sodium chloride (NaCl) has a molar mass 35.45 for chloride, which you find from looking up the atomic mass of chlorine on the periodic table and noting there is only 1 Cl ion per NaCl molecule. The mass of sodium doesn't come into play since we're only looking at chloride ions for this problem. So, you now have the relation:
35.45 gram/mole or 35.5 g/mol
You either move the decimal point over one space to the left or multiply this value times 0.1 to get the number of grams in a 0.1 M solution, to give you 3.55 grams per liter for a 0.1 M NaCl solu
tion. 3.55 g/L is the same as 3550 mg/L
Since 1 mg/L is about 1 ppm:
A 0.1 M solution of NaCl has a concentration of about 3550 ppm Cl ions.
Answer:
Va = (MbVb)/Ma
Explanation:
Divide both sides by Ma and voila!
It's likely what's wanted is
<span><span>Li</span>→<span><span>Li</span><span>2+</span></span>+2<span>e−
</span></span>
The reason is because IEs are usually reported from the neutral atom, that is, IE2 is the energy required to remove two electrons from a neutral Li atom, as above, rather than the additional energy required to remove one more electron from an Li+ cation.
I think answer should be c. Please give me brainlest let me know if it’s correct or not okay thanks
Answer:
39.2 L at STP
Explanation:
Convert the grams to moles first by dividing 56.0 by the molar mass of O2 (32.0) then convert to volume by multiplying by 22.4.
= 39.2 L
