All categories

3 years ago

A person uses 770 kcal on a long hike. Calculate the energy used for the hike in each of the following energy units.

Chemistry

1 answer:

Pavlova-9 [17]3 years ago

5 0

Explanation:

1 Cal of energy is equivalent to 4.184 Joules.

770Cal of energy = 3221.680 joules

Therefore, 780kCal of energy = 3221680 Joules.

3200000 Joules (in 2 s.f).

I000 joules = 1 kJoule

3221680 joules = 3221.689 kJoules.

3200 kJ (in 2 s.f).

You might be interested in

Density of iron is 7.8 g/cc. How much would 10 cc of iron weigh?

Elena-2011 [213]

Answer:

<h3>The answer is 78 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 10 cc

density = 7.8 g/cc

So we have

mass = 7.8 × 10

We have the final answer as

Hope this helps you

4 0

3 years ago

How does sustainable development support in a long term vision

vfiekz [6]

Explanation:

meet .google .com/sxr-wgwg-vnc

4 0

3 years ago

Read 2 more answers

How many grams of octane (C8H18) must be burned to produce 300.0g of CO2?

nika2105 [10]

Answer:

$m_{C_8H_{18}}=85.67gC_8H_{18}$

Explanation:

Hello there!

In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:

$m_{C_8H_{18}}=300.0gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molC_8H_{18}}{25molO_2}*\frac{114.22gC_8H_{18}}{1molC_8H_{18}} \\\\m_{C_8H_{18}}=85.67gC_8H_{18}$

Regards!

6 0

3 years ago

Points + Brainalist

Lorico [155]

Answer:

I think A it looks to be the answer

Explanation:

sorry if wrong

4 0

2 years ago

FIND THE RATIO BY MASS OF THE COMBINING ELEMENTS IN THE FOLLOWING COMPOUNDS

boyakko [2]

The given compound is Aluminum sulfate, Al2(SO4)3:

Molar masses:

Aluminum = 27 g/mol
Sulfur = 32 g/mol
Oxygen = 16 g/mol

The total molar mass is 342 g/mol
The ratio by mass of the elements:

Aluminum = 27*2/342
= 0.16
Sulfur = (32*3)/342
= 0.28
Oxygen = (16*12)/342
= 0.56
<span />

5 0

3 years ago