Answer:
(5/24) gallons of gas to mow the side yard
Step-by-step explanation:
We can easily solve this proble by applying a rule of three
5/16 gallons of gas --------------------------------- for 1 backyard
x gallons of gas ------------------------------------- 2/3 backyard
x = ((2/3)/1)*(5/16) gallons of gas
x = ((2/3))*(5/16) gallons of gas
x = ((10/48) gallons of gas
x = (5/24) gallons of gas
Step-by-step explanation:
f(3)=?
f(x)=2x+5
put x=3,
f(3)=2(3)+5=6+5=11
------------
g(2)=?
g(x)=x^2-3
put x=2,
g(2)=2^2-3=4-3=1
-----------------
g(f(-1))=?
g(x)=x^2-3
and f(-1)=2(-1)+5= -2+5=3
so g(f(-1))=3^2-3=9-3=6
----------------
f(g(-1))=?
f(x)=2x+5
g(x)=g(-1)=(-1)^2-3=1-3= -2
f(g(-1))=2(-2)+5= -4+5=1
----------------
g(f(x))=?
g(x)= x^2-3
put x=f(x),
g(f(x))=f(x)^2-3=(2x+5)^2-3=4x+25+20x-3=24x+25
Answer:
AM = 25, AC = 15, CM = 20
Step-by-step explanation:
The given parameters are;
In ΔACM, ∠C = 90°,
⊥
, AP = 9, and PM = 16
² +
² =
²
=
+ PM = 9 + 16 = 25
= 25
² =
² +
² = 9² +
²
∴
² = 9² +
²
Similarly we get;
² = 16² +
²
Therefore, we get;
² +
² = 9² +
² + 16² +
² =
² = 25²
2·
² = 25² - (9² + 16²) = 288
² = 288/2 = 144
= √144 = 12
From
² = 9² +
², we get
= √(9² + 12²) = 15
= 15
From,
² = 16² +
², we get;
= √(16² + 12²) = 20
= 20.