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Solnce55 [7]
3 years ago
12

What is the area of this figure I WILLLL GIVE BRAINLIEST​

Mathematics
1 answer:
MrMuchimi3 years ago
8 0
Answer:

217 ft^2

Step-by-step explanation:

Area for triangle is 1/2 bh

The b is the base and h is the height

For the base, 4 is included but we need to find the other piece for the base. so…

8 + 9 = 11 + ?

17 = 11 + ?

? = 17 - 11

? = 6

Then add 6 and 4

10

so the base of the triangle is 10. now…

10 x 7 = 70/2 = 35

The area of the triangle is 35

Now the square

8 x 7 = 56

The area of the square is 56

Finally the rectangle

9 x 14 = 126

The area of the rectangle is 126

Now add the areas for all of the shapes

35 + 56 + 126 = 217 ft^2

The area of the figure is 217 ft^2
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Princess Poly claims that the equation (3x−4i)(7x−8)(3x+4i)=0 has three roots, a real root and a complex root with a multiplicit
Serjik [45]

Given equation:

(3x-4i)(7x-8)(3x+4i)=0

i.e., 3x-4i=0       and       7x-8=0       and       3x+4i=0

i.e., 3x=4i       and       7x=8       and       3x=-4i

i.e., x=\frac{4i}{3}       and       x=\frac{8}{7}       and       x=-\frac{4i}{3}

Therefore, the given equation has a real root i.e., x=\frac{8}{7}

and two complex conjugate roots i.e., x=\frac{4i}{3} and x=-\frac{4i}{3}

Hence, option C is correct.

4 0
3 years ago
a mower uses 5/16 gallon of gas to mow the back yard. the side yard is only 2/3 the size of the backyard. How much gas will be n
Trava [24]

Answer:

(5/24) gallons of gas to mow the side yard

Step-by-step explanation:

We can easily solve this proble by applying a rule of three

5/16 gallons of gas  ---------------------------------  for 1 backyard

x  gallons of gas ------------------------------------- 2/3 backyard

x = ((2/3)/1)*(5/16) gallons of gas

x = ((2/3))*(5/16) gallons of gas

x = ((10/48) gallons of gas

x = (5/24) gallons of gas

3 0
4 years ago
Can someone slove this please
Morgarella [4.7K]
Hope this helps u.!!!

8 0
4 years ago
Pleaseee help!
user100 [1]

Step-by-step explanation:

f(3)=?

f(x)=2x+5

put x=3,

f(3)=2(3)+5=6+5=11

------------

g(2)=?

g(x)=x^2-3

put x=2,

g(2)=2^2-3=4-3=1

-----------------

g(f(-1))=?

g(x)=x^2-3

and f(-1)=2(-1)+5= -2+5=3

so g(f(-1))=3^2-3=9-3=6

----------------

f(g(-1))=?

f(x)=2x+5

g(x)=g(-1)=(-1)^2-3=1-3= -2

f(g(-1))=2(-2)+5= -4+5=1

----------------

g(f(x))=?

g(x)= x^2-3

put x=f(x),

g(f(x))=f(x)^2-3=(2x+5)^2-3=4x+25+20x-3=24x+25

7 0
4 years ago
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
3 years ago
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