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Arlecino [84]
3 years ago
6

-5 > -5 - 8w algebra answer

Mathematics
2 answers:
Gennadij [26K]3 years ago
5 0

Answer:

w > 0 --> solution

wariber [46]3 years ago
4 0

Answer:

w > 0

Step-by-step explanation:

-5 > -5 - 8w

+5   +5

--------------------

0 > -8w

/-8    /-8

--------------------

0 > w

w > 0

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$7.825 per hour × $32.125 hours round answer to the thousandth of a dollar???​
xenn [34]
Correct it is right u have to multipl
4 0
4 years ago
Use the disk method or the shell method to find the volume of the solid generated by revolving the region bounded by the graphs
JulsSmile [24]

Answer:

1) V = 12 π  ㏑ 3

2) \mathbf{V = \dfrac{328 \pi}{9}}

Step-by-step explanation:

Given that:

the graphs of the equations about each given line is:

y = \dfrac{6}{x^2}, y =0 , x=1 , x=3

Using Shell method to determine the required volume,

where;

shell radius = x;   &

height of the shell = \dfrac{6}{x^2}

∴

Volume V = \int ^b_{x-1} \ 2 \pi ( x) ( \dfrac{6}{x^2}) \ dx

V = \int ^3_{x-1} \ 2 \pi ( x) ( \dfrac{6}{x^2}) \ dx

V = 12 \pi \int ^3_{x-1} \dfrac{1}{x} \ dx

V = 12 \pi ( In \ x ) ^3_{x-1}

V = 12 π ( ㏑ 3 - ㏑ 1)

V = 12 π ( ㏑ 3 - 0)

V = 12 π  ㏑ 3

2) Find the line y=6

Using the disk method here;

where,

Inner radius r(x) = 6 - \dfrac{6}{x^2}

outer radius R(x) = 6

Thus, the volume of the solid is as follows:

V = \int ^3_{x-1} \begin {bmatrix}  \pi (6)^2 - \pi ( 6 - \dfrac{6}{x^2})^2  \end {bmatrix} \ dx

V  =  \pi (6)^2 \int ^3_{x-1} \begin {bmatrix}  1 - \pi ( 1 - \dfrac{1}{x^2})^2  \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  1 -  ( 1 + \dfrac{1}{x^4}- \dfrac{2}{x^2})  \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  - \dfrac{1}{x^4}+ \dfrac{2}{x^2} \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  {-x^{-4}}+ 2x^{-2} \end {bmatrix} \ dx

Recall that:

\int x^n dx = \dfrac{x^n +1}{n+1}

Then:

V = 36 \pi ( -\dfrac{x^{-3}}{-3}+ \dfrac{2x^{-1}}{-1})^3_{x-1}

V = 36 \pi ( \dfrac{1}{3x^3}- \dfrac{2}{x})^3_{x-1}

V = 36 \pi \begin {bmatrix} ( \dfrac{1}{3(3)^3}- \dfrac{2}{3}) - ( \dfrac{1}{3(1)^3}- \dfrac{2}{1})    \end {bmatrix}

V = 36 \pi (\dfrac{82}{81})

\mathbf{V = \dfrac{328 \pi}{9}}

The graph of equation for 1 and 2 is also attached in the file below.

5 0
4 years ago
Clyde’s age is 8 years more than thrice bonnie’s age. If the product of their ages is 80, how old is Clyde
Law Incorporation [45]

Answer:

20

Step-by-step explanation:

Let Bonnie's age = b.

Clyde's age is 8 year more than Bonnie's age, so Clyde's age is

3b + 8

The product of the ages is 80, so

b(3b + 8) = 80

3b^2 + 8b = 80

3b^2 + 8b - 80 = 0

(3b + 20)(b - 4) = 0

3b + 20 = 0 or b - 4 = 0

3b = -20 or b = 4

b = -20/3 or b = 4

Discard the negative answer since an age is not a negative number.

Bonnie's age is 4.

Clyde's age is 3 * 4 + 8 = 12 + 8 = 20.

Answer: Clyde's age is 20.

6 0
3 years ago
Let r(x)=x^2.If r(x)=4,find x
ElenaW [278]
The answer should be D
3 0
3 years ago
Distribute and Combine x-5(5x + 1)
gizmo_the_mogwai [7]

Answer:

7x-5

Step-by-step explanation:

x-5(5x-1) becomes 6x-5+1x-5. Once you simplify that, you get 7x-5.

8 0
3 years ago
Read 2 more answers
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