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stira [4]
3 years ago
13

A pipe 100 mm dia and 1 km long is to carry water from a reservoir to a village of 1000 people consuming 200 l/person/day. The p

ipeline works 8 hrs daily. The losses in the pipe including friction has been calculated as 10 m. The pressure to be maintained in the outlet is 25 kN/m2. What should be the height of the top of the reservoir assuming both the village and reservoir are situated in a plain?​
Engineering
2 answers:
natka813 [3]3 years ago
8 0

Answer:

i899999999999999999ijhhh

Explanation:

MrMuchimi3 years ago
8 0

Answer:

do the wam wam

Explanation:

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vampirchik [111]

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avoiding cutting down tree carelessy

Explanation:

people cutting down tree due to high population in order to find land for building this house so government should encourage people to have less children in the families and train them that when they are cutting trees should plants 10 tree inorder to recovery tree that is take off.

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Affordability is most concerned with:
leva [86]

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feasibility study

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When a person has the ability to move a vehicle, they have ____________________.
sergiy2304 [10]

(Energy ) i think .....

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3 years ago
Based on these statements:
Evgen [1.6K]

Answer:

the third statement is true

Explanation:

given data

Lenovos cost more than Dells

Lenovos cost less than Apples

solution

we have given 1st statement that is express as

cost (Lenovo) > cost (Dell)     ..................1

and

2nd statement that is express as

cost (Lenovo) < cost (Apple)

so we can say it as

cost (Apple) > cost (Lenovo)       ......................2

and

now above Both equation 1 and 2 can be written as

cost (Apple) > cost (Lenovo) > cost (Dell)      .........................3

so we can say cost of Apples is more than the cost of Lenovos and the cost of Dells

so as that given 3rd statement is true

7 0
3 years ago
Air with a mass flow rate of 2.3 kg/s enters a horizontal nozzle operating at steady state at 450 K, 350 kPa, and velocity of 3
viktelen [127]

Answer:

Given that

Mass flow rate ,m=2.3 kg/s

T₁=450 K

P₁=350 KPa

C₁=3 m/s

T₂=300 K

C₂=460 m/s

Cp=1.011 KJ/kg.k

For ideal gas

P V = m R T

P = ρ RT

\rho_1=\dfrac{P_1}{RT_1}

\rho_1=\dfrac{350}{0.287\times 450}

ρ₁=2.71 kg/m³

mass flow rate

m= ρ₁A₁C₁

2.3 = 2.71 x A₁ x 3

A₁=0.28 m²

Now from first law for open system

h_1+\dfrac{C_1^2}{200}+Q=h_2+\dfrac{C_2^2}{2000}

For ideal gas

Δh = CpΔT

by putting the values

1.011\times 450+\dfrac{3^2}{200}+Q=1.011\times 300+\dfrac{460^2}{2000}

Q=1.011\times 300+\dfrac{460^2}{2000}-\dfrac{3^2}{200}-1.011\times 450

Q= - 45.49 KJ/kg

Q =- m x 45.49 KW

Q= - 104.67 KW

Negative sign indicates that heat transfer from air to surrounding

4 0
2 years ago
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