Answer:
<em>50%</em>
Explanation:
Given
Initial power = 200W
Final power = 300W
Increment = 300 - 200 = 100W
percentage increase = increment/initial power * 100
percentage increase = 100/200 * 100%
percentage increase = 0.5 * 100
percentage increase = 50%
<em>Hence the percentage increase in speed is 50%</em>
Answer:
imma need a few answer choices so i can do my research
Explanation:
Please any thank you
The isobars in the conventional series that will be needed
to complete the pressure analysis between the lowest and highest values on this
map are: 1008, 1012, 1016, 1020.
To add, an isobar is <span>a line on a map connecting points having the
same atmospheric pressure at a given time or on average over a given period.</span>
Answer:
Approximately 
(assuming that the projectile was launched at angle of 
above the horizon.)
Explanation:
Initial vertical component of velocity:
.
The question assumed that there is no drag on this projectile. Additionally, the altitude of this projectile just before landing 
is the same as the altitude 
at which this projectile was launched: 
.
Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is 
(upwards,) the vertical velocity right before landing would be 
(downwards.) The change in vertical velocity is:
.
Since there is no drag on this projectile, the vertical acceleration of this projectile would be 
. In other words, 
.
Hence, the time it takes to achieve a (vertical) velocity change of 
would be:
.
Hence, this projectile would be in the air for approximately .
The other person who answered this is wrong btw
