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White raven [17]
3 years ago
7

What is the relationship between a community and a population?

Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
6 0

a community is a group of populations

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The correct formula for aluminum phosphide
rewona [7]
<span>Aluminium phosphide.....</span>
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4 years ago
Gerald's science teacher mixed room temperature samples of hydrochloric acid and sodium hydroxide in a large beaker. The solutio
Rama09 [41]

Answer:

A.

A chemical reaction was producing a new substance.

Explanation:

Equation of the reaction

NaOH + HCl --> NaCl + H2O

Heat of neutralization is the amount of heat evolved when one mole of acid reacts with one mole of an alkaline to form one mole of water.

When a neutralisation reaction is carried out, there is an exothermic change; energy released into the surroundings therefore since heat is given out which is what is felt.

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What happens when light strikes a transparent object?
bearhunter [10]

you can see the light coming through the other side easily

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4 years ago
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If 1 kilowatt-hour (kWh) = 3.60 × 10^6 J, which of the following conversion factors should be used to convert 56.7 kWh to J?
Nitella [24]

Answer:

c option is correct

Explanation:

May this help you!!!!!!

3 0
3 years ago
Determine the overall reaction and its standard cell potential (in V) at 25°C for the reaction involving the galvanic cell made
mel-nik [20]

Answer:

Standard cell potential is 0.56V

Explanation:

Standard reduction potential (E^{0}) are given below-

                             E_{Cu^{+}\mid Cu}^{0}=0.52V

                              E_{Fe^{3+}\mid Fe}^{0}=-0.04V

As E_{Cu^{+}\mid Cu}^{0} is greater than E_{Fe^{3+}\mid Fe}^{0} therefore Fe will be oxidized to Fe^{3+} and Cu^{+} will be reduced to Cu

Oxidation: Fe(s)-3e^{-}\rightarrow Fe^{3+}(aq.)

Reduction: Cu^{+}(aq.)+e^{-}\rightarrow Cu(s)

------------------------------------------------------------------------------------------------------

Overall: Fe(s)+3Cu^{+}(aq.)\rightarrow Fe^{3+}(aq.)+3Cu(s)

Standard cell potential, E_{cell}^{0}=E_{Cu^{+}\mid Cu}^{0}-E_{Fe^{3+}\mid Fe}^{0}=(0.52+0.04)V=0.56V

3 0
4 years ago
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