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Kamila [148]
3 years ago
15

I2 + Na2S2O3 → NaI + Na2S4O6 Balance the equation, if necessary.

Chemistry
2 answers:
Olin [163]3 years ago
8 0

Answer : The balanced chemical reaction will be,

I_2+2Na_2S_2O_3\rightarrow 2NaI+Na_2S_4O_6

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given unbalanced chemical reaction is,

I_2+Na_2S_2O_3\rightarrow NaI+Na_2S_4O_6

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of iodine, sulfur and oxygen are not balanced.

In order to balanced the chemical reaction, the coefficient 2 is put before the NaI and Na_2S_2O_3.

Thus, the balanced chemical reaction will be,

I_2+2Na_2S_2O_3\rightarrow 2NaI+Na_2S_4O_6

eduard3 years ago
3 0
I2 + 2 Na2S2O3 = 2 NaI + Na2S4O6

Reaction type double replacement
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o-na [289]

Answer:

vHe / vNe = 2.24

Explanation:

To obtain the velocity of an ideal gas you must use the formula:

v = √3RT / √M

Where R is gas constant (8.314 kgm²/s²molK); T is temperature and M is molar mass of the gas (4x10⁻³kg/mol for helium and 20,18x10⁻³ kg/mol for neon). Thus:

vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol

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The ratio is:

vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

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<em>vHe / vNe = 2.24</em>

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8 0
3 years ago
En un recipiente cerrado y rígido se introdujo una mezcla gaseosa a cierta temperatura y las presiones parciales de cada gas son
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Answer:

Qp > Kp, por lo tanto, la presión parcial de BrF₃(g) aumenta hasta alcanzar el equilibrio.

Explanation:

Paso 1: Escribir la ecuación balanceada

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Paso 2: Calcular el cociente de reacción (Qp)

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Paso 3: Sacar una conclusión

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3 years ago
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vesna_86 [32]

Explanation:

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where,    d_{H_{2}O} = density of water

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                       = -1.51 \times 10^{-6}        

Therefore, calculate the required pressure as follows.

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Hence, for change of 1 degree pressure the decrease is 145 bar  and for 4.7 degree change dP = 145 \times 4.7 bar

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F
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The statement is true in this situation is C. The size of Ffric is the same as the size of Fapp:

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So, ∑Fx = 0 and ∑Fy = 0

Since Fapp acts in the negative x - direction and Ffric acts in the positive x - direction,

∑Fx = -Fapp + Ffric = 0

-Fapp + Ffric = 0

Fapp = Ffric

Also, since Fgrav acts in the negative y - direction and Fnorm acts in the positive y - direction,

∑Fy = Fnorm + (-Fgrav) = 0

Fnorm - Fgrav = 0

Fnorm = Fgrav

So, we see that the size of Fapp <u>equals</u> size of Ffric and the size of Fnorm <u>equals</u> the size of Fgrav.

So, the correct option is C

The statement which is true in this situation is C. The size of Ffric is the same as the size of Fapp.

Learn more about equilibrium of forces here:

brainly.com/question/12980489

5 0
2 years ago
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