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3 years ago

How many mm are in 3.6 km?

Chemistry

2 answers:

FrozenT [24]3 years ago

8 0

Answer: 3.6e+6

Explanation:

Rainbow [258]3 years ago

6 0

Answer:

3.6km = 3.6e+6mm

Explanation:

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in 1990, the men's singles winner of the us. open tennis tournament has his serves clocked at 127 mi/hr. How fast must a 56.6 g

Naddika [18.5K]

This problem is providing information about the mass of a tennis ball, 56.6 g (0.0566 kg) and asks for the velocity it will have to equal the wavelength of green light, which is 5400 A or 540 nm (5.4x10⁻⁷ m). Thus, after doing the math, the result is 2.17x10⁻²⁶ m/s.

<h3>Broglie's wavelength:</h3>

In this case, we recall the formula of the Broglie's wavelength as shown below:

$\lambda =\frac{h}{mv}$

Whereas lambda is the wavelength, h is the Planck's constant, m the mass and v the speed; thus, we solve for the speed according to the question:

$v =\frac{h}{m\lambda}$

<h3>Calculations:</h3>

Then, we just plug in the numbers we were given to get the answer:

$v =\frac{6.626x10^{-34} kg*\frac{m^2}{s} }{0.056kg*5.4x10^{-7}m}\\\\v=2.17x10^{-26}m/s$

Learn more about Broglie's wavelength: brainly.com/question/5440536

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2 years ago

A mixture of gases with a pressure of 800.0 mm hg contains 60% nitrogen and 40% oxygen by volume. what is the partial pressure o

klasskru [66]

Hello!

<span>We have the following statement data:
</span>
Data:
$P_{Total} = 800 mmHg$
$P\% N_{2} = 60\%$
$P\% O_{2} = 40\%$
$P_{partial} = ? (mmHg)$

<span>As the percentage is the mole fraction multiplied by 100:

</span> $P = X_{ O_{2} }*100$

<span>The mole fraction will be the percentage divided by 100, thus:
</span><span>What is the partial pressure of oxygen in this mixture?
</span>
$X_{ O_{2} } = \frac{P}{100}$
$X_{ O_{2}} = \frac{40}{100}$
$\boxed{X_{ O_{2}} = 0.4}$

<span>To calculate the partial pressure of the oxygen gas, it is enough to use the formula that involves the pressures (total and partial) and the fraction in quantity of matter:
</span>
In relation to $O_{2}$ :

$\frac{P O_{2} }{P_{total}} = X_O_{2}$
$\frac{P O_{2} }{800} = 0.4$
$P_O_{2} = 0.4*800$
$\boxed{\boxed{P_O_{2} = 320\:mmHg}}\end{array}}\qquad\quad\checkmark$
<span>
Answer:
</span><span>b. 320.0 mm hg </span>

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3 years ago

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Answer:

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Explanation:

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natta225 [31]

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