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hammer [34]
2 years ago
10

How many mm are in 3.6 km?

Chemistry
2 answers:
FrozenT [24]2 years ago
8 0

Answer: 3.6e+6

Explanation:

Rainbow [258]2 years ago
6 0

Answer:

3.6km = 3.6e+6mm

Explanation:

You might be interested in
One situation indicates a physical change rather than a chemical change. which situation indicates a physical change
Goryan [66]

if you were to fold a piece of paper into a bunch of pieces.

Explanation:

its just a different shape but it's still the same piece of paper

3 0
3 years ago
An irregular chunk of iron has a density of 7.87 g/cm3. A 14.5 gram chunk is added to a graduated cylinder. If the final volume
bulgar [2K]

Answer:

37.96 mL

Explanation:

From the question given above, the following data were obtained:

Density (D) of iron = 7.87 g/cm³

Mass (m) of iron = 14.5 g

Volume of Cylinder + Iron = 39.8 mL

Volume of Cylinder =?

Next, we shall determine the volume of the chunk of iron. This can be obtained as follow:

Density (D) of iron = 7.87 g/cm³

Mass (m) of iron = 14.5 g

Volume (V) of iron =?

D = m/V

7.87 = 14.5 /V

Cross multiply

7.87 × V = 14.5

Divide both side by 7.87

V = 14.5 / 7.87

V = 1.84 cm³

Recall:

1 cm³ = 1 mL

Therefore,

1.84 cm³ = 1.84 mL

Therefore, the volume of the chunk of iron is 1.84 mL.

Finally, we shall determine the starting volume of the cylinder as follow:

Volume of Cylinder + Iron = 39.8 mL

Volume of Iron = 1.84 mL.

Volume of Cylinder =?

Volume of Cylinder = (Volume of Cylinder + Iron) – Volume of Iron

Volume of Cylinder = 39.8 – 1.84

Volume of Cylinder = 37.96 mL

Therefore the starting volume of cylinder is 37.96 mL

3 0
3 years ago
Using the mass of a proton 1.0073 amu and assuming it's diameter is1.0x10^-15, calculate the density of a proton in g/cm^3. I'm
valkas [14]
You just have to find a conversion from amu to grams. For every 1 amu, there is 1.66×10⁻²⁴ grams. Thus,

Mass of proton = 1.0073 amu * 1.66×10⁻²⁴ grams/amu = 1.672×10⁻²⁴ grams

Since a proton is spherical in shape, the volume would be:

Volume = 1/6*πd³ = 1/6*π(1.0×10⁻¹⁵ cm)³ = 5.236×10⁻⁴⁶ cm³

Therefore, the density is equal to

Density = Mass/Volume = 1.672×10⁻²⁴ grams/5.236×10⁻⁴⁶ cm³
Density = 3.2×10²¹ g/cm³
4 0
3 years ago
Which of these steps should always be followed for effective problem solving? a. buying a larger quantity of material than estim
Nesterboy [21]
The best steps that should always be used for effective problem solving would be C. Developing a plan and then implementing the plan.
3 0
3 years ago
Read 2 more answers
How to prepare hydrogen gas​
Ghella [55]
1. Natural Gas Reforming/Gasification: Synthesis gas, a mixture of hydrogen, carbon monoxide, and a small amount of carbon dioxide, is created by reacting natural gas with high-temperature steam. ...

2. Electrolysis: An electric current splits water into hydrogen and oxygen.

Hope this helps :))
4 0
2 years ago
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