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Serhud [2]
2 years ago
12

If I leave 750 mL of 0.75 M sodium chloride solution uncovered on a windowsill and 150 mL of the solvent evaporates, what will t

he new concentration of the sodium chloride solution be? M1V1 = M2V2
Chemistry
1 answer:
MAVERICK [17]2 years ago
8 0
M1V1=M2V2

V2=750-150=600 ml

0.75M*750 ml = M2*600

M2=0.75*750/600 ≈ 9.38 M
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2 years ago
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With 21 g of Zinc, and 7 g of CuCl2, how much ZnCl2 is made in grams?
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Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}    

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According to stoichiometry :

1 mole of CuCl_2 require 1 mole of Zn

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Thus CuCl_2 is the limiting reagent as it limits the formation of product and Zn is the excess reagent.

As 1 mole of CuCl_2 give = 1 mole of ZnCl_2

Thus 0.052 moles of CuCl_2 give =\frac{1}{1}\times 0.052=0.052moles  of ZnCl_2

Mass of ZnCl_2=moles\times {\text {Molar mass}}=0.052moles\times 136g/mol=7.07g

Thus 7.07 g of ZnCl_2 will be produced from the given masses of both reactants.

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