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hram777 [196]
3 years ago
7

How many unpaired electrons are in a neutral atom of chlorine?

Chemistry
1 answer:
Bas_tet [7]3 years ago
6 0
₁₇Cl 1s²2s²2p⁶3s²3p⁵, 1 unpaired electron in 3pz orbital.
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How can the chemical properties of an element help determine the types of materials it can form?
AleksandrR [38]
<h2><u>Answer:</u></h2>

The quantity of protons likewise decides the character of the component. Electrons have a negative charge. The furthest or valence electrons of a particle are the ones that partake in synthetic responses. A component's substance properties rely upon its valence electrons.  

The general properties of issue, for example, shading, thickness, hardness, are instances of physical properties. Properties that portray how a substance changes into a totally extraordinary substance are called synthetic properties. Combustibility and consumption/oxidation obstruction are instances of compound properties.  

Reactivity with other chemicals.

Toxicity.

Coordination number.

Flammability.

Enthalpy of formation.

Heat of combustion.

Oxidation states.

Chemical stability

5 0
3 years ago
Which of the following is the<br> correct way to express<br> 0.0000321 in scientific<br> notation?
scZoUnD [109]
The answer is 3.21*10^-5
7 0
3 years ago
A solution of is found to have 37% transmittance at 447 nm. If the molar absorption coefficient (ε) is 4400 at 477 nm, what is t
inn [45]

Answer:

The concentration of the solution is 1.068×10⁻⁴M

Explanation:

Hello,

To find the concentration of the solution, we'll have to use Beer-Lambert law which states absorption is directly proportional to the concentration of the solution.

Beer-Lambert law = A = εCL

A = absorption = 2 - log₁₀%T = 2 - log₁₀(34)

A = 2 - 1.5314 = 0.47

A = 0.47

ε = molar absorption coefficient = 4400

C = concentration of the solution

L = path length = 1cm

A = εcl

C = A / εl

C = 0.47 / 4400 × 1

C = 1.068×10⁻⁴M

The concentration of the solution is 1.068×10⁻⁴M

3 0
3 years ago
14. Which of the following is produced when propane (C3H8) is combusted completely? (2 points)
Ymorist [56]

The following is produced when propane (C₃H₈) is combusted completely : H₂O

<h3>Further explanation  </h3>

Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.  

If O₂ is insufficient there will be incomplete combustion produced by CO and H and O  

Hydrocarbon combustion reactions (especially alkanes)  \large {\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 \Rightarrow nCO_2 + (n + 1) H_2O}}}

For combustion of propane C₃H₈ (n = 3) ⇒ completely(excess O₂) :

C₃H₈+5O₂⇒3CO₂+4H₂O

The products of combustion : CO₂ and H₂O

7 0
3 years ago
Can someone please help me thx!!!
Rudik [331]

Answer:

the answer should be A

Explanation:

hope this helps you.

6 0
3 years ago
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