Answer: 1.48971 x 10^19
Step-by-step explanation: 1-light year is approximately 5.865 x 10^12 which is 5,865,000,000,000 kilometers or 6 trillion miles in 1-year. The Andromeda galaxy is indeed 2.54 million light-years from Earth which is the closest galaxy to our Milky Way Galaxy.
The best way to this is to put this into a scientific calculator. If it shows 1.48971E19, the E stands for exponent and the 19 next to the E stands to the 19th power. That is written as 1,489,710,000,000,000,000 miles!! from Earth. That's a lot of zeros. That's the reason scientific notation is used; to avoid all those zeros and express very small/large figures.
Hope this explanation helps.
Answer:
6:55 A. M. is the latest time he can leave his house
90x^2+15x-30 (hope this helps)
3.14/5.71=0.18330414466 years
hope this hepls
Answer:
a. v(t)= -6.78
+ 16.33 b. 16.33 m/s
Step-by-step explanation:
The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=
=
. We now multiply both sides of the equation by the integrating factor.
μv' + μkv = μg ⇒ v' + kv = g ⇒ [v]' = g. Integrating, we have
∫ [v]' = ∫g
v = 
+ c
v(t)= + c
.
From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have
9.55 = 9.8 × 15/9 + c
= 16.33 + c
c = 9.55 -16.33 = -6.78.
So, v(t)= 16.33 - 6.78. m/s = - 6.78 + 16.33 m/s
b. Velocity of object at time t = 0.5
At t = 0.5, v = - 6.78
+ 16.33 m/s = 16.328 m/s ≅ 16.33 m/s
