A range check is often used when a person works with data consisting of numbers, dates and times, or currency, ensuring that a number is within a specific range.
Explanation:
- Range checks allow a person to set suitable boundaries.
- An example of a range check is checking to see if the value of a 16-bit integer is within the capacity of a 16-bit integer. When a range check is performed, upper and lower boundaries are specified.
- Range check is a validation check which can be applied to numeric fields. This is done to ensure that only numbers within a certain domain can be entered into a field. Remember that this does not necessarily mean that the data entered will be correct. But it will certainly lie within reasonable limits.
- A method of validation which checks that data falls between an upper and lower acceptable value.
- This validation check which can be applied to numeric fields. This is done to ensure that only numbers within a certain domain can be entered into a field. Remember that this does not necessarily mean that the data entered will be correct. But it will certainly lie within reasonable limits.
Answer:
The code to this question can be given as:
code:
tp = ip;
ip = jp;
jp = tp;
Explanation:
In this question, it is defined that write code for swapping values that swap the pointers, not the values they point to. So in this code, we assume that all the variable and its value is defined. we simply use the swapping rule that is the first value holds in the new variable and second value hold on the first variable and in the last second variable holds the value of the new variable. In this code, the value will be interchanged or swapped.
Answer:
Check the explanation
Explanation:
Keep two iterators, i (for nuts array) and j (for bolts array).
while(i < n and j < n) {
if nuts[i] == bolts[j] {
We have a case where sizes match, output/return
}
else if nuts[i] < bolts[j] {
what this means is that the size of nut is lesser than that of bolt and we should go to the next bigger nut, i.e., i+=1
}
else {
what this means is that the size of bolt is lesser than that of nut and we should go to the next bigger bolt, i.e., j+=1
}
}
Since we go to each index in both the array only once, the algorithm take O(n) time.
