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3 years ago

What causes a rolling object

Physics

1 answer:

Serjik [45]3 years ago

7 0

Gravity but when it is rolling it has kinetic energy.

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Please please help I'm stuck!!!

Korvikt [17]

Answer: iDc im in 3grade

Explanation:sorry

6 0

2 years ago

Read 2 more answers

How does the intensity of a sound wave change if the distance from the

Alex17521 [72]

Answer:

The new intensity decreases by a factor of 16.

Explanation:

The intensity of sound wave is given by :

$I=\dfrac{P}{A}$

P is power

A is area

$I=\dfrac{P}{4\pi r^2}$

$I\propto \dfrac{1}{r^2}$ , r is distance from the source

If the distance from the source is increased by a factor of 4, r' = 4r

So,

$I'=\dfrac{1}{r'^2}\\\\I'=\dfrac{1}{(4r)^2}\\\\I'=\dfrac{1}{16}\times \dfrac{1}{r^2}\\\\I'=\dfrac{I}{16}$

So, the new intensity decreases by a factor of 16.

8 0

3 years ago

Savatey [412]

Answer:

Distance covered is equal to all the distance traveled.

So for example, if you go from A to B, and then from B to C, the total distance covered is AB + BC.

Displacement is equal to the difference between the final position and the initial position.

So if we go from A to B, the displacement is simply the line AB.

While if we go from A to B, and then from B to C, the displacement will be a segment that directly connects A and C, such that:

displacement = √( (AB)^2 + (BC)^2)

Now, if we want to find the points such that the magnitude of the distance covered is equal to the magnitude of the displacement, we need to look at the pairs that are directly connected by a straight line.

Those are:

A to B ( or B to A)

B to C (or C to B)

C to D (or D to C)

7 0

3 years ago

Un automovil parte del reposo y acelera uniformemente hasta alcanzar una rapidez de 0,255km/h en un tiempo de 3/4 Minutos determ

Elden [556K]

Answer:

a = 1.5*10^-3 m/s^2

x = 0.033m = 3.3cm

Explanation:

To calculate the acceleration and the distance traveled by the car you use the following formulas:

$v=v_o+at$ (1)

$x=v_ot+\frac{1}{2}at^2$ (2)

v: final velocity = 0,255 km/h

vo: initial velocity = 0 m/s

t: time = 3/4 min

a: acceleration = ?

x: distance

In order to use the equations (1) and (2) you first convert the units of the final velocity to m/s, and the time to seconds.

$v=0,255\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}\\\\v=0.07m/s\\\\t=\frac{3}{4}min*\frac{60s}{1min}=45s$

Next, you solve the equation (1) for the acceleration a:

$a=\frac{v}{t}=\frac{0.07m/s}{45s}=1.5*10^{-3}\frac{m}{s^2}$

With this value of a you can calculate the distance traveled by the car, by using the equation (2):

$x=\frac{1}{2}(1.5*10^{-3}m/s^2)(45s)^2=0.033m=3.3cm$

hence, the acceleration of the car is 1.5*10^-3 m/s^2 and the distance traveled in 3/4 min is 0.033m

5 0

3 years ago

A particular atom becomes more energetically stable when it loses a single electron. It is most likely an atom of which of the f

Scorpion4ik [409]

Answer:

Magnesium (Mg)

Explanation:

because i checked

6 0

2 years ago