Which pair of substances would most likely result in the production of a solid when reacting with a base?
2 answers:
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Compounds which on dissolving in water gets completely dissociates into its ions are known as strong electrolytes whereas compounds which on dissolving in water gets partially dissociates into its ions are known as weak electrolytes.
Substances which gives solution on dissolving in water and do not dissociates into ions also does not conduct electric current are known as nonelectrolyte.
- Hydrochloric acid,
On adding (strong acid) in water, it will completely dissociates into ions (
and
) and thus, it is a strong electrolyte.
- Sodium hydroxide,
On adding (strong base) in water, it will completely dissociates into ions (
and
) and thus, it is a strong electrolyte.
- Formic acid,
On adding (weak acid) in water, it will partially dissociates into ions (
and
) and thus, it is a weak electrolyte.
- Methyl amine,
On adding (weak base) in water, it will partially dissociates into ions (
and
) and thus, it is a weak electrolyte.
- Potassium chloride,
On adding in water, it will completely dissociates into ions (
and
) and thus, it is a strong electrolyte.
- Ethanol,
On adding in water, it will not dissociates into ions and thus, it is a nonelectrolyte.
- Sucrose,
On adding in water, it will not dissociates into ions and thus, it is a nonelectrolyte.
<u>Answer:</u> The enthalpy of the reaction is 269.4 kJ/mol
<u>Explanation:</u>
To calculate the heat absorbed by the calorimeter, we use the equation:
where,
q = heat absorbed
c = heat capacity of calorimeter = 675 J/°C
= change in temperature =
Putting values in above equation, we get:
To calculate the heat absorbed by water, we use the equation:
where,
q = heat absorbed
m = mass of water = 925 g
c = heat capacity of water = 4.186 J/g°C
= change in temperature =
Putting values in above equation, we get:
Total heat absorbed =
Total heat absorbed =
To calculate the enthalpy change of the reaction, we use the equation:
where,
q = amount of heat absorbed = 134.7 kJ
n = number of moles of hydrocarbon = 0.500 moles
= enthalpy change of the reaction
Putting values in above equation, we get:
Hence, the enthalpy of the reaction is 269.4 kJ/mol