All categories

3 years ago

PLEASSE help its homework

Chemistry

2 answers:

tiny-mole [99]3 years ago

8 0

Answer:

What homework? i dont see a picture, can u tell me the question?

Explanation:

Alborosie3 years ago

6 0

There is no picture. It just says please help it’s homework. Sorry! If you want to put it in the comments maby I can help.

You might be interested in

What does this mean<br><br> 1.000 atm=101.3kpa

jenyasd209 [6]

Answer:

The standard value of atmospheric pressure at sea level

Explanation:

3 0

3 years ago

Balancing equations

Bad White [126]

Make sure you numbers with variable are on one side and the numbers

7 0

4 years ago

How many moles of chloride ions are there in 2.5 L of 5 M magnesium chloride?

castortr0y [4]

Answer:

$n_{Cl^-}=25molCl^-$

Explanation:

Hello,

In this case, since the given 5-M concentration of magnesium chloride is expressed as:

$5\frac{molMgCl_2}{L}$

We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:

$n_{Cl^-}=5\frac{molMgCl_2}{L}*\frac{2molCl^-}{1molMgCl_2} *2.5L\\\\n_{Cl^-}=25molCl^-$

Best regards.

4 0

3 years ago

A mixture contains only NaCl and Al2(SO4)3. A 1.45-g sample of the mixture is dissolved in water, and an ex- cess of NaOH is add

chubhunter [2.5K]

Answer:

The mass percent of aluminum sulfate in the sample is 16.18%.

Explanation:

Mass of the sample = 1.45 g

$Al_2SO_3+6NaOH\rightarrow 2Al(OH)_3+3Na_2SO_4$

Mass of the precipitate = 0.107 g

Moles of aluminum hydroxide = $\frac{0.107 g}{78 g/mol}=0.001372 mol$

According to reaction, 2 moles of aluminum hydroxide is obtained from 1 mole of aluminum sulfate .

Then 0.001372 moles of aluminum hydroxide will be obtained from:

$\frac{1}{2}\times 0.001372 mol=0.000686 mol$

Mass of 0.000686 moles of aluminum sulfate :

= 0.000686 mol × 342 g/mol = 0.2346 g

The mass percent of aluminum sulfate in the sample:

$=\frac{ 0.2346 g}{1.45g}\times 100=16.18\%$

5 0

3 years ago

What coefficients must be added to balance the following reaction __Sn+___H3PO4___=H2+___Sn3(PO4)4

BARSIC [14]

Answer 3Sn+ 4H3pO4= 6H2+Sn(PO)4

1 Sn 3 Sn
3 H 2 H
1 P 4 P
4 O 16 O
then you have to make the numbers the same for each side

so you get by putting the 3 infront of Sn 4 infront of the H3PO4 and 6 infront of the H2
3 Sn 3 Sn
12 H 12 H
4 P 4 P
16 O 16 O

5 0

3 years ago