1 newton is the force needed to accelerate 1 kilogram of mass
at the rate of 1 meter per second² .
1 N = 1 kg-m/s² .
It's a force equal to roughly 3.6 ounces.
Answer:
=3.5 m/s
Explanation:
y = x tanθ - 1/2 g x² / (u²cos²θ )
y = 0.25 , x = 0.5, θ = 40°
.25 = .50 tan40 - .5 x 9.8x x²/ u²cos²40
.25 = .42 - 2.0875/u²
u = 3.5 m / s.
The difference in electric potential energy between the two points is

where q is the magnitude of the charge and

is the electric potential difference.
But for energy conservation, the difference in electric potential energy

between the two points is equal to the work done to move the charge between A and B:

so we have

and by substituting the numbers of the problem, we find the value of

:
C i would think
it sounds best
Answer: 10Nm or 10J
Explanation:
Given the following :
Force (f) = 5
Distance (d) = 2m
Calculate the kinetic energy assuming no friction
Work done = force × distance
Work done = 5N × 2m = 10Nm
Recall :
Work done = ΔK.E ( change in kinetic energy)
Therefore, kinetic energy of the book after sliding = ΔK. E, which is equal to work done.
Hence, K. E of book after sliding is 10Nm