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Aleksandr [31]
4 years ago
10

A baseball player was hit by a baseball in the left eye and complains of double vision. What should you do? A. Restrict spinal m

ovement B. Assess pupillary response C. Perform a detailed exam D. Apply ice to orbit
Physics
2 answers:
Korolek [52]4 years ago
5 0
I would say C. because the other choices don’t really relate to the situation
Alex4 years ago
4 0
I think the smartest answer would be C sorry if i’m writing though
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Which carbon reservoirs did not receive any carbon?
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Need a picture of the problem
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3 years ago
If the ultraviolet photon has a wavelength of 249 nm and one of the photons emitted by the fluorescent material has a wavelength
melamori03 [73]

Answer:

601 nm

Explanation:

Energy of photon having wavelength of λ nm

= \frac{1244}{\lambda}eV

Energy of 249 nm photon

=\frac{1244}{249}

=4.996 eV

Similarly energy of 425nm photon

=\frac{1244}{425}

=2.927 eV

Difference = 2.069 eV.

This energy will give rise to another photon whose wavelength will be

λ = \frac{1244}{2.069}

= 601 nm.

6 0
4 years ago
A string of length L, mass per unit length \mu, and tension T is vibrating at its fundamental frequency. What effect will the fo
viva [34]

The fundamental frequency on a vibrating string is given by:

f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}

where

L is the length of the string

T is the tension

\mu is the mass per unit length of the string

Keeping this equation in mind, we can now answer the various parts of the question:

(a) The fundamental frequency will halve

In this case, the length of the string is doubled:

L' = 2L

Substituting into the expression of the fundamental frequency, we find the new frequency:

f'=\frac{1}{2(2L)}\sqrt{\frac{T}{\mu}}=\frac{1}{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{2}

So, the fundamental frequency will halve.

(b) the fundamental frequency will decrease by a factor \sqrt{2}

In this case, the mass per unit length is doubled:

\mu'=2\mu

Substituting into the expression of the fundamental frequency, we find the new frequency:

f'=\frac{1}{2L}\sqrt{\frac{T}{2 \mu}}=\frac{1}{\sqrt{2}}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{\sqrt{2}}

So, the fundamental frequency will decrease by a factor \sqrt{2}.

(c) the fundamental frequency will increase by a factor \sqrt{2}

In this case, the tension is doubled:

T'=2T

Substituting into the expression of the fundamental frequency, we find the new frequency:

f'=\frac{1}{2L}\sqrt{\frac{2T}{\mu}}=\sqrt{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\sqrt{2}f

So, the fundamental frequency will increase by a factor \sqrt{2}.

8 0
4 years ago
This scientist focused his study on planetary motion. One of his laws is the planets orbit the Sun in elliptical patterns.
Savatey [412]
I believe that since Kepler focused his studies the rotation of the planets, and the stars, that he is the one who developed the law, which is called the first law of planetary motion.
8 0
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The farthest major planet from the sun is
nikdorinn [45]

The farthest major planet from the sun is Neptune

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