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sergij07 [2.7K]
3 years ago
10

You throw a glob of putty straight up toward the ceiling, which is 3.50 mm above the point where the putty leaves your hand. The

initial speed of the putty as it leaves your hand is 9.50 m/sm/s. Part A What is the speed of the putty just before it strikes the ceiling
Physics
1 answer:
LuckyWell [14K]3 years ago
5 0

Answer: 4.65\ m/s

Explanation:

Given

Distance putty has to travel is 3.5 m

The initial speed of putty is 9.50 m/s

Using equation of motion to determine the velocity of putty just before it hits ceiling

v^2-u^2=2as

\Rightarrow v^2-(9.5)^2=2(-9.8)(3.5)\\\\\Rightarrow v^2=9.5^2-68.6\\\Rightarrow v=\sqrt{90.25-68.6}\\\Rightarrow v=4.65\ m/s

So, the velocity of putty just before hitting is 4.65\ m/s

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A 190 N child is in a swing that is attached to ropes 2.10 m long. Find the gravitational potential energy of the child-Earth sy
Alekssandra [29.7K]

Answer:

a) Gravitational potential energy = 399 J

b) Gravitational potential energy = 66.5 J

c) Gravitational potential energy = 0 J

Explanation:

Hi there!

Please, see the attached figure for a better understanding of the problem.

a) When the ropes are horizontal, the height of the child, relative to the child's lowest position, is 2.10 m (see figure).

The gravitational potential energy is calculated as follows:

PE = mgh

Where:

PE = potential energy.

mg = weight of the child

h = height.

Then when the ropes are horizontal, the potential energy will be:

PE = 190 N · 2.10 m = 399 J

b) When the ropes make a 34.0° with the vertical, the height of the child is 2.10 m minus x (see figure). To find x, we can use trigonometry of right triangles:

cos angle = adjacent side / hypotenuse

cos 34.0° = x / 2.10 m

x = 2.10 m · cos 34.0° = 1.75 m

Then, the height of the child relative to the lowest position is

(2.10 m - 1.75 m) = 0.35 m

Therefore, the gravitational potential energy will be:

PE = 190 N · 0.35 m

PE = 66.5 J

c) When the child is at the bottom of the circular arc the height is zero (the child is at the lowest position), then, the gravitational potential energy will be zero.

6 0
3 years ago
What other angle would give the same range at 19 degrees?
yaroslaw [1]

Answer:

I think it is acute angle.

Explanation:

Because it is an angle between 0° and 90°. Hope this answer wil help you.

8 0
3 years ago
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to what circuit element is an ideal inductor equivalent for circuits with constant currents and voltages?
Marat540 [252]

Answer:

Short circuit

Explanation:

In an ideal inductor circuit with constant current and voltage, it implies that the voltage drop in the circuit is zero (0).

Also, In circuit analysis, a short circuit is defined as a connection between two nodes that forces them to be at the same voltage.

In an ideal short circuit, this means there is no resistance and thus no voltage drop across the connection. That is voltage drop is zero (0).

Therefore, the circuit element is short circuit.

8 0
3 years ago
In a parallel circuit that has the same number and type of resistors as a series circuit the total resistance will be __________
zloy xaker [14]

Answer:

B. lower, greater

...............

6 0
3 years ago
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The device shows the relative humidity at 22 degrees celsius. What's the water vapor density if the maximum water vapor in air a
sweet [91]

Answer:

11.6 g/m³

Explanation:

The complete question is,

The device shows the relative humidity at 22 degrees celsius. What's the water vapor density if the maximum water vapor in air at this temperature is 20 gram/cubic meter? a device showing that at 22 degrees celsius the relative humidity is 58%.

Solution:

saturation of water in air is showed by the relative humidity. As it is 58% and not 100%. Lets scale density that we have, if humidity is 100%.

density is 20 gram/m³ when the humidity is 100%

When humidity is 58%

0.58 x 20 = 11.6 g/m³

Therefore, density is 11.6g/m³

6 0
3 years ago
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