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sergij07 [2.7K]
2 years ago
10

You throw a glob of putty straight up toward the ceiling, which is 3.50 mm above the point where the putty leaves your hand. The

initial speed of the putty as it leaves your hand is 9.50 m/sm/s. Part A What is the speed of the putty just before it strikes the ceiling
Physics
1 answer:
LuckyWell [14K]2 years ago
5 0

Answer: 4.65\ m/s

Explanation:

Given

Distance putty has to travel is 3.5 m

The initial speed of putty is 9.50 m/s

Using equation of motion to determine the velocity of putty just before it hits ceiling

v^2-u^2=2as

\Rightarrow v^2-(9.5)^2=2(-9.8)(3.5)\\\\\Rightarrow v^2=9.5^2-68.6\\\Rightarrow v=\sqrt{90.25-68.6}\\\Rightarrow v=4.65\ m/s

So, the velocity of putty just before hitting is 4.65\ m/s

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A neurogenic bladder is a urinary problem caused by interference with the normal __________ associated with urination.
Elena L [17]

Answer:

nerve pathways

Explanation:

It is called Neurogenic Bladder (VN) to any alteration of bladder behavior due to a pathology of the central and / or peripheral nervous system. It may consist of the loss of storage and / or urine disposal capabilities. Thus, a lesion in the upper centers causes variation in storage capacity, but if peripheral innervation is affected, loss of emptying capacity occurs. In the case of patients with spinal cord injury (ML) there are changes in both at the same time.

3 0
3 years ago
Please answer it fast and correctly​
ivanzaharov [21]

Answer:

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(3) Arrangements for functions had been made by him

(4) A meeting is being attended by Raman

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3 0
3 years ago
Zorn and Porsha are ice skating. Porsha has a mass of 60 kg, and Zorn has a mass of 40 kg. As they face each
algol13

Assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Missing part of the question: determine the magnitude of Porsha's acceleration.

Given the data in the question;

  • Mass of Porsha; m_{porsha} = 60kg
  • Mass of Zorn; m_{zorn} = 40kg
  • Force of Porsha push; F_{porsha} = 168N

Magnitude of Porsha's acceleration; a = \ ?

To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:

F = m*a

Where m is the mass of the object and a is the acceleration.

We substitute the mass of Porsha and the force he used into the equation

168N = 60kg * a\\\\a = \frac{168kg.m/s^2}{60kg}\\\\a = 2.8m/s^2

Therefore, assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Learn more: brainly.com/question/25125444

3 0
2 years ago
An alarm clock has a resistance of 14,000 ohms and is plugged into a 120-volt outlet. How much power does the clock use?
yan [13]

Power used by the clock=1.03 W

Explanation:

resistance= 14000 ohm

voltage=120 V

The formula for the power is given by

P=\frac{V^{2}}{R}

P=(120)²/14000

P=1.03 W

8 0
3 years ago
Read 2 more answers
A transverse mechanical wave is traveling along a string lying along the x-axis. The displacement of the string as a function of
Wewaii [24]

(1) The wavelength of the wave is 1.164 m.

(2) The  velocity of the wave is 23.7 m/s.

(3) The maximum speed in the y-direction of any piece of the string is 6.14 m/s.

<h3> Wavelength of the wave</h3>

A general wave equation is given as;

y(x, t) = A sin(Kx - ωt)

<h3>Velocity of the wave</h3>

v = ω/K

From the given wave equation, we have,

y(x, t) = 0.048 sin(5.4x - 128t)

v = ω/K

where;

  • ω corresponds to 128
  • k corresponds to 5.4

v = 128/5.4

v = 23.7 m/s

<h3>Wavelength of the wave</h3>

λ = 2π/K

λ = (2π)/(5.4)

λ = 1.164 m

<h3>Maximum speed of the wave</h3>

v(max) = Aω

where;

  • A is amplitude of the wave
  • ω is angular speed of the wave

v(max) = (0.048)(128)

v(max) = 6.14 m/s

Thus, the wavelength of the wave is 1.164 m.

The  velocity of the wave is 23.7 m/s.

The maximum speed in the y-direction of any piece of the string is 6.14 m/s.

Learn more about wavelength here: brainly.com/question/10728818

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1 year ago
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