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jonny [76]
3 years ago
9

A boat Pulls a 60Kg water-skier with a force of 105 N, What is the skier’s acceleration?

Chemistry
1 answer:
kicyunya [14]3 years ago
8 0

Answer:1.75 acceleration

Explanation: because 105N divide by 60kg = 1.75

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Consider the following set of ions: Al3+; Li+, Rb+, [(C4H9)4N+].
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Hey there!:

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3 0
3 years ago
What is the half-life of an isotope that decays to 12.5% of its original activity in 19.8 hours?
katen-ka-za [31]
x= x_{0}  e^{kt} ,where~ x ~is~ the ~ |amount\ of \material\ at\ any~~time~t

and~ x_{0} ~the~original~amount.
when~x=  \frac{12.5}{100} x_{0}  }= \frac{125}{1000}  x_{0}
\frac{x}{ x_{0} } = \frac{125}{1000}= \frac{1}{8}
when t=19.8 hrs,
x= x_{0}  e^{19.8 k}, 
 \frac{x}{ x_{0} } = e^{19.8 k}, 
 \frac{1}{8} = e^{19.8k} ,
ln \frac{1}{8} =19.8 k,

ln1-ln8=19.8k,
0-ln 2^{3} =19.8 k,
-3 ln2=19.8k
k= \frac{-3 ln2}{19.8} = \frac{- ln 2}{6.6}x= x_{0}  e^{ \frac{-ln2}{6.6}t } ,
 \frac{x}{ x_{0} } = e^{ \frac{- ln 2}{6.6}t } 
\frac{1}{2} = e^{ \frac{- ln2}{6.6}t } = \frac{1}{ e^{ \frac{ln 2}{6.6} t} } ,
2= e^{ \frac{ln2}{6.6}t } ,
ln2=ln  e^{ \frac{ln 2}{6.6}t } = \frac{ln 2}{6.6} t~ln e= \frac{ln2}{6.6} t,
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