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Natali [406]
3 years ago
13

Please help. Having a hard time figuring out

Physics
1 answer:
Goryan [66]3 years ago
5 0
Yeah that’s is correct
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A cube with sides of area 22 cm2 contains a 21.2 nanoCoulomb charge. Find the flux of the electric field through the surface of
VladimirAG [237]

Answer:

Explanation:

According to Gausses theorem, electric flux coming out of  charge   on all sides q is equal to

q / ε₀

q is charge , ε₀  is permittivity of air whose value is given by

8.85 x 10⁻¹²; q = 21.2 x 10⁻⁹ C

Putting the values we get

FLUX = \frac{21.2\times10^{-9}}{8.85\times10^{-12}}

2.4 x 10³ Nm²/C

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3 years ago
WILL MARK BRAINLIEST!<br> WORTH A LOT OF POINTS!
Shalnov [3]

Answer:

A is your anwser

Explanation:

4 0
3 years ago
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What is the momentum of a man of mass 10kg when he walks with a uniform velocity of 2m/s.
Stolb23 [73]

Answer:

Momentum(p) = 20kgm/s

Explanation:

Given

Mass = 10kg

Velocity = 2m/s

Required

Calculate the momentum of the man

Momentum is calculated as thus

Momentum(p) = Mass(m) * Velocity(v)

or

p = mv

So; to solve this question; we simply substitute 10kg for mass and 2m/s for velocity in the above formula;

The formula becomes

Momentum(p) = 10kg * 2m/s

Momentum(p) = 10 * 2 * kg * m/s

Momentum(p) = 20kgm/s

Hence, the momentum of the man is 20kgm/s

5 0
3 years ago
A ferry approaches shore, moving north with a speed of 6.2 m/s relative to the dock. A person on the ferry walks from one side o
jasenka [17]

Speed of Ferry is towards North with magnitude 6.2 m/s

Here if we assume that North direction is along Y axis and East is along X axis then we can say

\vec v_f = 6.2 \hat j

Now a person walk on ferry with speed 1.5 m/s towards east with respect to Ferry

so it is given as

\vec v_{pf} = 1.5 \hat i

also by the concept of relative motion we know that

\vec v_{pf} = \vec v_p - \vec v_f

now plug in all values in it

1.5 \hat i = \vec v_p - 6.2 \hat j

\vec v_p = 1.5 \hat i + 6.2 \hat j

now if we need to find the speed of the person then we need to find its magnitude

so it is given as

v = \sqrt{1.5^2 + 6.2^2}

v = 6.37 m/s

7 0
3 years ago
You weigh 580 N on Earth. If you were to go to Mars, where its gravitational pull is 3 . 7 11 m /s 2 , what would you weigh? (Hi
andrew-mc [135]

Answer:

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