<span>The maxima of an equation can be obtained by taking the 1st
derivative of the equation then equate it to 0.</span>The value of N that result in best yield is when dy/dn = 0.
Taking the 1st derivative of
the equation y=(kn)/(9+n^2) :<span>
</span>
By using the quotient
rule the form of the equation is:<span>
y = g(n) / h(n)
where:</span>
g(n) = kn --->
g'(n) = k
<span>
<span>h(n) = 9 + n^2 ---> h'(n) = 2n </span>
dy/dn is defined as:
<span>dy/dn = [h(n) * g'(n) - h'(n) * g(n)] / h(n)^2
dy/dn = [(9 + n^2)(k) - (kn)(2n)] / (9 +
n^2)^2
dy/dn = (9k + kn^2 - 2kn^2) / (9 + n^2)^2
dy/dn = (9k - kn^2) / (9 + n^2)^2
dy/dn = k(9 - n^2) / (9 + n^2)^2
<span>Equate dy/dn = 0, then solve for n
k(9 - n^2) / (9 + n^2)^2 = 0
k(9 - n^2) = 0
9 - n^2 = 0
n^2 = 9
n = sqrt(9)
n = 3
<span>Answer: The nitrogen
level that gives the best yield of agricultural crops is 3 units.</span></span></span></span>
Answer:
The rate of heat rejection will be 347 GJ/hr
Explanation:
We have given that power plant uses energy of 365 GJ/hr
So energy uses 
Work done from turbine 
We have to find the rate of heat rejection to the atmosphere 
We know that 


So the rate of heat rejection will be 347 GJ/hr
Answer:
Explanation:
Given
time for which spacecraft turned on is 789 s




we know 



For y component




Answer:
R = ½ R₀
Explanation:
This is an exercise in Ohm's law,
V = IR
in the initial case
V₀ = I₀ R₀ (1)
indicates that the voltage remains constant and the current is doubled
I = 2 I₀
V₀ = I R
we substitute
V₀ = 2 I₀ R
R = ½ V₀ / I₀
we replace by equation 1
R = ½ R₀