Question

Quick brainliest asap!! sin^-1 (1.1976) SHOW YOUR WORK so I can see if it makes sense!!

Answer 1

Answer:

no solutions

Step-by-step explanation:

We want to find $\theta$ such that $\theta=\sin^{-1}(1.1976)$.

We can take the sine of both sides of the equation to get$\sin(theta)=\sin(\sin^{-1}(1.1976))=1.1976$.

We know that the range of the sine function goes from -1 to 1 inclusive, so there is no value $\theta$ such that $\sin{\theta}>1$.

Therefore, the answer is $\boxed{no~solutions}$ and we're done!