Just subtract the whole numbers, 5.93-5 = 0.93.
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =
(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =
= 2a^3 - 2(a^3)/3 = [4/3](a^3)
Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3
ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =
Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
So first you find 10% which is 34.5
Then you multiply 10% by 4 to get 40% which is = 138
Answer:
540°.
Step-by-step explanation:
On a unit circle, cos θ = -1 at 180°.
However, cos θ has a period of 2π, or 360°. This means that cos θ will equal to -1 again after 2π.
To solve for the angle:
180° + 360° = 540°. This is the next angle at which cos θ = -1.
Answer:
75%
Step-by-step explanation:
as a percent = 75%, or 0.75 in decimal form.
