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MariettaO [177]
3 years ago
9

Which is a solvent in a cup of juice drink?

Physics
1 answer:
RoseWind [281]3 years ago
3 0

Answer:

D. water because the ice cubes the powdered juice and the sugar can be dissolve in water so the solvent is water

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What is the magnitude of the minimum magnetic field that will keep the particle moving in the earth's gravitational field in the
Zepler [3.9K]

Answer:

The magnitude of the magnetic field vector is 1.91T and is directed towards the east.

The steps to the solution can be found in the attachment below.

Explanation:

For the charge to remain in the the earth' gravitational field the magnetic force on the charge must be equal to the earth's gravitational force on the charge and must act opposite the direction of the earth's gravitational force.

Fm = Fg

qvBSin(theta) = mg

Where q = magnitude of charge

v = magnitude of the velocity vector = 4 x10^4 m/s

B = magnitude of the magnetic field vector

theta = the angle between the magnetic field and velocity vectors = 90°

m = mass of the charge = 0.195g

g = acceleration due to gravity =9.8m/s²

On substituting the respective values of all variables in the equation (1) above

B = 1.91T

The direction of the magnetic field vector was found by the application of the right hand rule: if the thumb is pointed in the direction of the magnetic force and the index finger is pointed in the direction of the velocity vector, the middle finger points in the direction of the magnetic field.

Below is the step by step procedure to the solution.

3 0
3 years ago
A hockey puck sliding along frictionless ice with speed v to the right collides with a horizontal spring and compresses it by 1.
patriot [66]

Answer:

The spring's maximum compression will be 2.0 cm

Explanation:

There are two energies in this problem, kinetic energy K= \frac{mv^{2}}{2} and elastic potential energy U= \frac{kx^{2}}{2} (with m the mass, v the velocity, x the compression and k the spring constant. ) so the total mechanical energy at every moment is the sum of the two energies:

E=K+U

Here we have a situation where the total mechanical energy of the system is conserved because there are no dissipative forces (there's no friction), so:

E_{i}=E_{f}

K_{i}+U_{i}=K_{f}+U_{f}

Note that at the initial moment where the hockey puck has not compressed the spring all the energy of the system is kinetic energy, but for a momentary stop all the energy of the system is potential elastic energy, so we have:

K_{i} = U_{f}

\frac{mv^{2}}{2}=\frac{kx^{2}}{2} (1)

Due conservation of energy the equality (1) has to be maintained, so if we let k and m constant x has to increase the same as v to maintain the equality. Therefore, if we increase velocity to 2v we have to increase compression to 2x to conserve the equality. This is  2(1.0) = 2.0 cm

7 0
3 years ago
5. A child rides a pony on a circular track with a radius of 5 m Find the distance traveled and the placement
Step2247 [10]

Answer:

gu kha muji haru sala

Explanation:

oemuji

4 0
3 years ago
g An object with mass m=2 kg is completely submerged, and tethered, to the bottom of a large body of water. If the density of th
Anit [1.1K]

Answer:

The tension in the rope is 20 N

Solution:

As per the question:

Mass of the object, M = 2 kg

Density of water, \rho_{w} = 1000\ kg/m^{3}

Density of the object, \rho_{ob} = 500\kg/m^{3}

Acceleration due to gravity, g = 10\ m/s^{2}

Now,

From the fig.1:

'N' represents the Bouyant force and T represents tension in the rope.

Suppose, the volume of the block be V:

V = \frac{M}{\rho_{ob}}              (1)

Also, we know that Bouyant force is given by:

N = \rho_{w}Vg

Using eqn (1):

N = \rho_{w}\frac{M}{\rho_{ob}}g

N = 1000\frac{2}{500}\times 10 = 40\ N

From the fig.1:

N = Mg + T

40 = 2(10) + T

T = 40 - 20 = 20 N

N = \rho_{w}Vg

3 0
3 years ago
A 0.20-f capacitor is desired. what area must the plates have if they are to be separated by a 3.2-mm air gap?
Igoryamba
Air gap means that the dielectric is air.

So <span>ε0 = </span><span>8.85 x 10^-12 [F/m].......................permitivity of free space

Lets use the equation

</span>C= ( ε0x A) / d

Where A is the area of the plate

And d the distance between the plates

d = <span>3.2-mm = 3.2 E-3 m

so ............> A = C *d /</span>ε0 = 0.20 F * 3.2 E-3 m /  8.85 x 10^-12 [F/m]

A = 7.23 E 7 [m2]
5 0
3 years ago
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