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Margarita [4]
3 years ago
9

A 10 kg block is attached to a light cord that is wrapped around the pulley of an electric motor, as shown above. If the motor r

aises the block from the floor to a height of 8.0 meters in 5 seconds what was the motor’s power output?

Physics
1 answer:
Anika [276]3 years ago
7 0

Answer:

156.8 Watts

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 10 kg

Height (h) = 8 m

Time (t) = 5 s

Power (P) =?

Next, we shall determine the energy used by the motor to raise the block. This can be obtained as follow:

Mass (m) = 10 kg

Height (h) = 8 m

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E) =?

E = mgh

E = 10 × 9. 8 × 8

E = 784 J

Finally, we shall determine the power output of the motor. This can be obtained as illustrated below:

Time (t) = 5 s

Energy (E) = 784 J

Power (P) =?

P = E/t

P = 784 / 5

P = 156.8 Watts

Therefore, the power output of the motor is 156.8 Watts

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3 years ago
A person in bare feet is standing under a tree during a thunderstorm, seeking shelter from the rain. A lightning strike hits the
Anni [7]

Answer:

I=38.181\ A is the current through the body of the man.

E=34.5\ J energy dissipated.

Explanation:

Given:

  • time for which the current lasted, t=43\times 10^{-6}\ s
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  • resistance between the feet, R=550\ \Omega

<u>Now, from the Ohm's law we have:</u>

I=\frac{V}{R}

I=\frac{21000}{550}

I=38.181\ A is the current through the body of the man.

<u>Energy dissipated in the body:</u>

E=I^2.R.t

E=38.181^2\times 550\times 43\times 10^{-6}

E=34.5\ J

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hopefully this'll help

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