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Mariulka [41]
4 years ago
7

If you are driving 128.4 km/h along a straight road and you look down for 3.0s, how far do you travel during this inattentive pe

riod?
Physics
1 answer:
ser-zykov [4K]4 years ago
8 0

Answer:

107 m

Explanation:

Convert km/h to m/s:

128.4 km/h × (1000 m / km) × (1 h / 3600 s) = 35.67 m/s

Distance = rate × time

d = 35.67 m/s × 3.0 s

d = 107 m

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A railroad car of 2000 kg coasting at 3.0 m/s overtakes and locks with an identical car coasting on the same track in the same d
serg [7]
The key is in "they lock together". This tells you this is a complete inelastic collision and therefore you can use the formula:
m1*v1+m2*v2=v(m1+m2)
Plug in numbers:
2000*3+2000*2=v(2000+2000)
so v=2 m/s, obviously in the same direction of motion in which they were both moving.
4 0
4 years ago
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o
Schach [20]

Explanation:

The given data is as follows.

       Temperature of metal = 296^{o}C = (296 + 273) K

                                            = 569 K

     Density of the metal = 8.85 g/cm^{3} = 8.85 \times 10^{-6} g/m^{3}      (as 1 cm^{3} = 10^{-6} m^{3})

     Atomic mass = 51.40 g/mol

    Vacancies = 9.19 \times 10^{23} m^{-3}

Formula to calculate the number of atomic sites is as follows.

           n = \frac{\rho \times N_{A}}{\text{atomic weight}}

              = \frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}

              = 1.036 \times 10^{17} atom/m^{3}

Now, we will calculate the energy as follows.

                E = -KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})

where,    K = 8.62 \times 10^{-5}

         E = -8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})

               = 78.46 eV/atom

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is 78.46 eV/atom.

6 0
4 years ago
4. As Juan is going to take a shower, the soap falls out of the soap dish on to the
LiRa [457]

The coefficient of friction between the soap and the floor is 0.081

If Juan steps on the soap with a force of 493 N, this is her weight, W. This weight also equals the normal reaction on the floor, N.

We know that frictional force F = μN where μ = coefficient of friction between soap and floor.

So, μ = F/N

Since F = 40 N and N = W = 493 N,

μ = F/N

μ = 40 N/493 N

μ = 0.081

So, the coefficient of friction between the soap and the floor is 0.081

Learn more about coefficient of friction here:

brainly.com/question/13923375

5 0
3 years ago
When a wave hits an object,energy from the wave is both absorbed and reflected off the object
poizon [28]
I believe the statement is true. Have a good day.
5 0
3 years ago
The archerfish uses a remarkable method for catching insects sitting on branches or leaves above the waterline. The fish rises t
Degger [83]

Answer:

The height above the waterline that the stream reaches at the horizontal position of the insect is 15 cm.

Explanation:

Please, see the attached figure for a description of the problem.

The motion is parabolic and this is the equation that describes the position of an object in such a motion:

r = (x0 + v0 · t · cos α, y0 + v0 · t · sin α  + 1/2 · g · t²)

Where:

r = position vector

x0 = initial horizontal position

v0 = initial velocity

t = time

α = angle of the stream with the waterline

y0 = initial vertical position

g = acceleration due to gravity

First, let´s calculate how much time it takes the stream to reach the horizontal position of 0.27 m. For this, we will use the equation of the x-component of the vector position:

x = x0 + v0 · t · cos α

Since the origin of the reference system is located at the mouth of the fish, x0 = 0. Then:

0.27 m = 3.7 m/s · t · cos 35º

t = 0.27 m /(3.7 m/s · cos 35º)

t = 0.089 s

Now, with this time, we can calulate the vertical position (height) of the stream using the equation for the y-component of the vector "r":

y = y0 + v0 · t · sin α  + 1/2 · g · t²

y = 0 m + 3.7 m/s · 0.089 s · sin 35º + 1/2 · (-9.8 m/s²) · (0.089s)²

y = 0.15 m

when the stream reaches 27 cm horizontally, it will reach 15 cm vertically and hit the insect!

3 0
4 years ago
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