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3 years ago

An arrow is shot at 27.0° above the horizontal. Its velocity is 54 m/s, and it hits the target.

Physics

1 answer:

GuDViN [60]3 years ago

3 0

Explanation:

(a) What is the maximum height the arrow will attain?

Given:

v₀ᵧ = 54 sin 27.0° m/s = 24.5 m/s

vᵧ = 0 m/s

aᵧ = -9.8 m/s²

Find: Δy

vᵧ² = v₀ᵧ² + 2aᵧΔy

(0 m/s)² = (24.5 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 30.7 m

(b) The target is at the height from which the arrow was shot. How far away is it?

Given:

Δy = 0 m

v₀ᵧ = 54 sin 27.0° m/s = 24.5 m/s

aᵧ = -9.8 m/s²

Find: t

Δy = v₀ᵧ t + ½ aᵧt²

0 m = (24.5 m/s) t + ½ (-9.8 m/s²) t²

t = 5.00 s

Given:

v₀ₓ = 54 cos 27.0° m/s = 48.1 m/s

aₓ = 0 m/s²

t = 5.00 s

Find: Δx

Δx = v₀ₓ t + ½ aₓt²

Δx = (48.1 m/s) (5.00 s) + ½ (0 m/s²) (5.00 s)²

Δx = 241 m

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3 years ago

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A metal cylinder measures 3.0 cm in diameter, is 12.0 cm high, and has a mass of 750 g. The cylinder hangs from a string attache

kvasek [131]

Answer with Explanation:

We are given that

Diameter of cylinder, $d_1=$ 3 cm

Radius, $r_1=\frac{d_1}{2}=\frac{3}{2}=1.5cm=1.5\times 10^{-2} m$

1m=100 cm

Height,h=12 cm= $\frac{12}{100}=0.12 m$

Mass,m=750 g= $\frac{750}{1000}=0.75kg$

1kg=1000 g

Diameter of beaker, $d_2=10 cm$

Radius of beaker, $r_2=\frac{d_2}{2}=\frac{10}{2}=5cm$

A. $\pi r^2_2h_2=\pi r^2_1 h_1$

$h_2=\frac{r^2_1}{r^2_2}h$

$h_2=\frac{(1.5)^2}{(5)^2}\times 12=1.08 cm$

Hence, the height of the water in the beaker rises when the cylinder is submerged=1.08 cm

B.Weight read on the scale after the cylinder is submerged

$w=mg-\rho A_1h_1g$

Where $g=9.8 m/s^2$

$A_1=\pi r^2_1$

Density of water= $\rho=1000kg/m^3$

$w=0.75\times 9.8-1000\times \pi(1.5\times 10^{-2})^2\times 0.12\times 9.8$

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3 years ago

Light of wavelength 510 nm is used to illuminate normally two glass plates 24.3 cm in length that touch at one end and are separ

bulgar [2K]

Answer:

$m = 180 \ bright \ fringes$

Explanation:

From the question we are told that

The wavelength is $\lambda = 510 \ nm = 510 *10^{-9} \ m$

The length of the of the plate is $l = 24.3 \ cm = 0.243 \ m$

The radius of the wire is $r= 0.023 \ mm = 2.3 *10^{-5} \ m$

Generally the diameter of the wire which is the distance between the glass plates is mathematically represented as

$d = 2 * r$

=> $d = 2 * 2.3 *10^{-5}$

=> $d = 4.6 *10^{-5} \ m$

Generally the condition for constructive interference is mathematically represented as

$2 *d = m \lambda$

=> $m = \frac{2d}{\lambda}$

=> $m = \frac{2 * (4.6* 10^{-5})}{ 510 *10^{-9} }$

=> $m = 180 \ bright \ fringes$

3 0

2 years ago

A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming

omeli [17]

Answer:

12.32 m/s

Explanation:

Using the formula of maximum height of a projectile,

H = u²sin²Ф/2g................... Equation 1

Where H = maximum height, u = initial velocity, Ф = angle of projection, g = acceleration due to gravity

make u the subject of the equation

u = √(2Hg/sin²Ф)............ Equation 2

Given: H = 2.3 m, Ф = 33°, g = 9.8 m/s²

Substitute into equation 2

u = √[(2×2.3×9.8)/sin²33°]

u =√ [45.08/(0.545)²]

u = 45.08/0.297

u = √(151.785)

u = 12.32 m/s

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3 years ago

You are in your car at rest when the traffic light turns green. You place your coffee cup on the horizontal dash and hit the gas

umka21 [38]

Answer:

(d) Negative.

Explanation:

let's test each at a time.

(a) It can't be 0, because cup would slide back other wise.

(b) Positive, well if forward is positive, than the work done against the forward acceleration must be negative , so it can't be positive.

well no, because work done by car's engine dosen't go all of it into getting car to move, so it can't be that.

(d) negative, this look like it, because work that friction does must be nagative to counteract positive thrust of car which is positive and in forward direction.

(d) this can't be true.

So the answer is (d) negative.

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