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Vlad [161]
3 years ago
13

Solve the proportion. If necessary, round to the nearest hundredth.

Mathematics
1 answer:
Elanso [62]3 years ago
8 0

Answer:

......the right answer is 12

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Theo had a balance of -$24 in his savings account. After making a deposit, he has $40 in his account. What is the overall change
never [62]

Answer:

16

Step-by-step explanation:

7 0
3 years ago
ILL MARK BRAINLIESTTTTT
zaharov [31]

Answer:

0.075 inches per year

Step-by-step explanation:

The average rate of change is measured as

( difference in diameter ) ÷ ( difference in years )

= ( 251 - 248 ) ÷ ( 2005 - 1965 )

= 3 inches ÷ 40 years

= 0.075 inches per year

7 0
3 years ago
Simplify 2.1 + (-3.7m) + 1.9m - 1.4
belka [17]

Answer:

-1.8m + 0.7

Step-by-step explanation:

4 0
3 years ago
Simultaneously x-2y=0 40-y=14​
harkovskaia [24]

Answer:

x = 52, y = 26

Step-by-step explanation:

x - 2y = 0

40 - y = 14​

(40 - 40) - y = 14​ - 40

- y = -26

y = 26

x - 2(26) = 0

x - 52 = 0

x (- 52 + 52) = 0 + 52

x = 52

7 0
3 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
Read 2 more answers
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