Answer:
double covalent bond
Explanation:
Double covalent bond -
It is the type of interaction observed between two species , which share the electrons in order to attain stability , is referred to as covalent bond.
The shared electrons are referred to as the bonding pairs or the shared pairs .
Stability and completion of the octet is the driving force for the formation covalent bond.
The molecules of the organic compound usually shows this type bonding .
A double covalent bond is the one which have four shared pair of electrons , i.e. two covalent bonds.
Hence , from the question,
Oxygen is capable to show double covalent bond .
Answer:
C. One mole of water was produced from this reaction.
Explanation:
- From the balanced equation:
<em>2H₂ + O₂ → 2H₂O,</em>
It is clear that 2 mol of H₂ react with 1 mol of O₂ to produce 2 mol of H₂O.
- So, if one mole of hydrogen was used in this reaction:
1/2 mol of O₂ was used in the reaction, and
1 mol of water was produced from this reaction.
- So, the correct statement is:
<em>C. One mole of water was produced from this reaction.
</em>
The crackling sound Is mainly to do with chemistry, The fireworks are filled with lead oxide, which turns into lead atoms as the firework explodes and heat up—— whistling sounds, the whistle is down to the tube being narrow one, thus rockets make a whistling noise
Answer:
ΔH°rxn = -827.5 kJ
Explanation:
Let's consider the following balanced equation.
2 PbS(s) + 3 O₂(g) → 2 PbO(s) + 2 SO₂(g)
We can calculate the standard enthalpy of reaction (ΔH°rxn) from the standard enthalpies of formation (ΔH°f) using the following expression.
ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g)
)] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g)
)]
ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g)
)] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g)
)]
ΔH°rxn = [2 mol × (-217.32 kJ/mol) + 2 mol × (-296.83)] - [2 mol × (-100.4) + 3 mol × 0 kJ/mol]
ΔH°rxn = -827.5 kJ
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