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Helen [10]
4 years ago
6

A 2.50-l volume of hydrogen measured at â196 °c is warmed to 100 °c. calculate the volume of the gas at the higher temperature

, assuming no change in pressure
Chemistry
1 answer:
ivann1987 [24]4 years ago
5 0

To solve this we assume that the hydrogen gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = (100 + 273.15) K x 2.50 L / (-196 + 273.15) K

<span>V2 = 12.09 L</span>

Therefore, the volume would increase to 12.09 L as the temperature is increased to 100 degrees Celsius.

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Unknown halogen X2 was added to each of two test tubes which contained aqueous NaCl and aqueous NaI, respectively. When hexane w
weeeeeb [17]

Answer:

Br_2

Explanation:

The compound X_2 is Br_2.

The reaction included are:

Br_2+NaCl--> No\ reaction  (because  bromine is less reactive than chlorine)

But , because of hexane the solution get dilute and its color changes to orange.

Now, NaI is added and we know Br is more reactive than I.

Therefore it replace it.

Reaction: Br_2+NaI-->NaBr+I_2

Purple color develop due to formation of Iodine.

7 0
3 years ago
A chemistry student needs 30,0 mL of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the stu
Marta_Voda [28]

Answer:

1.878g

Explanation:

Volume = 30.0ml

Density = 0.626gcm−3

Mass = ?

Be careful in this kind of questions to check for the units. In this case one has to remember 1 mL equal 1 cm³ so density = 0.626g/ml

The relationship between all three parameters is given by the equationn below;

Mass = Density * Volume

Mass = 0.626g/ml * 30 = 1.878g

8 0
3 years ago
Rick is creating a love potion for Morty. To make the potion, Rick's needs 51 mL of a mixture solution where 40% is carbonated w
Deffense [45]

Answer:

The amount of the first solution rick needs to mix together to create the love portion is 8.5 mL

Explanation:

So as to make the love potion, we have;

The percentage of carbonated water in the love portion = 40%

The percentage of green tea in the first solution = 65%

The percentage of carbonated water in the first solution = 15%

The percentage of whole milk in the first solution = 20%

The percentage of orange juice in the second solution = 17%

The percentage of lemonade in the second solution = 38%

The percentage of carbonated water in the second solution = 45%

Let 'x' represent the volume in mL of the first solution added to make the love portion, and let 'y' be the volume in mL of the second solution added to make the love portion, we have;

x + y = 51...(1)

0.15·x + 0.45·y = 0.40×51 = 20.4

0.15·x + 0.45·y = 20.4...(2)

Solving the system of simultaneous equation by making 'y' the subject of each of the equation gives;

For equation (1)

y = 51 - x

For equation (2)

y = 20.4/0.45 - (0.15/0.45)·x = 136 - 3·x

y = 136/3 - (1/3)·x

Equating the two equations of 'y', gives;

51 - x = 136/3 - (1/3)·x

51 - 136/3 = x - (1/3)·x

17/3 = (2/3)·x

(2/3)·x = 17/3

x = (3/2) × (17/3) = 17/2 = 8.5

x = 8.5

y = 51 - x = 42.5

y = 42.5

Therefore, the amount of the first solution rick needs to mix together to create the love portion, x = 8.5 mL

8 0
3 years ago
Please help me. I will mark you as a brainleist.​
Tasya [4]

Answer:

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3 0
3 years ago
The table shows the thickness, top density, and bottom
OleMash [197]

\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}

As depth increases, the density of the layers decreases.

  • Thanks.
  • Hope it helps.
3 0
3 years ago
Read 2 more answers
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