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Helen [10]
4 years ago
6

A 2.50-l volume of hydrogen measured at â196 °c is warmed to 100 °c. calculate the volume of the gas at the higher temperature

, assuming no change in pressure
Chemistry
1 answer:
ivann1987 [24]4 years ago
5 0

To solve this we assume that the hydrogen gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = (100 + 273.15) K x 2.50 L / (-196 + 273.15) K

<span>V2 = 12.09 L</span>

Therefore, the volume would increase to 12.09 L as the temperature is increased to 100 degrees Celsius.

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A sample of gas in a closed container at a temperature of 100oC and 3 atm is heated to 300oC. What is the pressure of the gas at
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6.14 atm

Explanation:

Initial temperature (T₁) = 100 °C

Initial pressure (P₁) = 4 atm

Final temperature (T₂) = 300 °C

Final pressure (P₂) =?

NOTE: Volume = constant (since the system is a closed system)

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 100 °C

Initial temperature (T₁) = 100 °C + 273 = 373 K

Final temperature (T₂) = 300 °C

Final temperature (T₂) = 300 °C + 273 = 573 K

Finally, we shall determine the pressure at the highest temperature as follow:

Initial temperature (T₁) = 373 K

Initial pressure (P₁) = 4 atm

Final temperature (T₂) = 573 K

Final pressure (P₂) =?

P₁ / T₁ = P₂ / T₂

4 / 373 = P₂ / 573

Cross multiply

373 × P₂ = 4 × 573

373 × P₂ = 2292

Divide both side by 373

P₂ = 2292 / 373

P₂ = 6.14 atm

Thus, the pressure at the highest temperature is 6.14 atm

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