Answer:
Answer is
A. I = 6.3×10^8 A
B. Yes
C. No
Refer below.
Explanation:
Refer to the picture for brief explanation.
The best way in handling in this situation is that in order for the astronaut to be able to get back to the shuttle is that he or she should take an object from his or her tool belt and to be thrown out away from the shuttle. This will allow her to weight lightly and safely return to the shuttle and would be easier for his or her to do so.
I can't draw you the graph right now because i'm out but look up graphing calculator and click on the first one, type in your equation and it will show you the graph
Answer:
A. T=126N
B. T=63N
Explanation:
To determine the tension in each given blocks, we first determine the acceleration of each block. It obvious that each mass will move with the same acceleration since the string connecting them is massless.
Hence using the equation of force we have
F=ma
Where m=total mass of blocks,
a=acceleration
F= force applied in this case the tension in the string.
For a 134 identical masses with an applied force of 134N, the acceleration of each mass can be computed as
134=134m*a
a=134/134m
a=(1/m )m/s²
a. To calculate the tension in the string between the 126 and 127 block, we use the equation below
T=ma
Since the number of blocks before the string is 126, we multiply the mass of each block by 126.
Hence the tension can be computed as
T=126m*a
Since a=1/m then
T=126m*1/m
T=126N
B.To calculate the tension in the string between the 63 and 64 block, we use the equation below
T=ma
Since the number of blocks before the string is 63, we multiply the mass of each block by 63.
Hence the tension can be computed as
T=63m*a
Since a=1/m then
T=63m*1/m
T=63N
High digital and high are the answers.
hope this helps
