The acceleration and distance is related to the following expression:
y=v0*t + a*t^2/2 ; v0=0
y=44.1*100/2 = 2205m
hence, the speed will be
v=0 + a*t = 441m/s
from that height it will just be subjected to the gravitational acceleration
0=v_acc^2 -2g*y_free
y_free = v_acc^2/2g = 9922.5m
<span>y_max = y_acc+y_free = 441+9922.5 =10363.5m</span>
Answer:
2 charges of electron (2C)
Explanation:
I = Q/t
2 = Q/1
Q = 2×1= 2C
Q = 2 charge of electron
Answer:
Height = 53.361 m
Explanation:
There are two balloons being thrown down, one with initial speed (u1) = 0 and the other with initial speed (u2) = 43.12
From the given information we make the following summary
= 0m/s
= t
= 43.12m/s
= (t-2.2)s
The distance by the first balloon is

where
a = 9.8m/s2
Inputting the values

The distance traveled by the second balloon

Inputting the values

simplifying

Substituting D of the first balloon into the D of the second balloon and solving

Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment

Reduce friction because friction just makes things harder