1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
schepotkina [342]
2 years ago
15

With which of the following is the weak nuclear force associated

Physics
1 answer:
BaLLatris [955]2 years ago
5 0
You need to post a picture bro
You might be interested in
.<br><img src="https://tex.z-dn.net/?f=25%20%7B%3F%7D%5E%7B%3F%7D%20%20%5Ctimes%20%5Cfrac%7B%3F%7D%7B%3F%7D%20" id="TexFormula1"
mr_godi [17]

Answer:

what is your exact question.

5 0
2 years ago
Read 2 more answers
Estimate how far apart the rays of deepest red and deepest violet light are as they exit the bottom surface. assume nred = 1.57
Harlamova29_29 [7]
We begin by noting that the angle of incidence is the one that's taken with respect to the normal to the surface in question. In this case the angle of incidence is 30. The material is Flint Glass according to the original question. The refractive indez of air n1=1, the refractive index of red in flint glass is nred=1.57, finally for violet in the glass medium is nviolet=1.60. Snell's Law dictates:
n_1sin(\theta_1)=n_2sin(\theta_2)
Where \theta_2 differs for each wavelenght, that means violet and red will have different refractive indices in the glass.
In the second figure provided details are given on which are the angles in question, \Delta x is the distance between both rays.
\theta_{2red}=Asin(\frac{sin(30)}{1.57})\approx 18.5705
\theta_{2violet}=Asin(\frac{sin(30)}{1.60})\approx 18.21
At what distance d from the incidence normal will the beams land at the bottom?
For violet we have:
d_{violet}=h.tan(\theta_{2violet})\approx 0.0132m
For red we have:
d_{red}=h.tan(\theta_{2red})\approx 0.0134m
We finally have:
\Delta x=d_{red}-d_{violet}\approx2.8\times10^{-4}m


6 0
3 years ago
How light is channelled down an optical fibre
coldgirl [10]

Explanation:

Suppose you want to shine a flashlight beam down a long, straight hallway. Just point the beam straight down the hallway -- light travels in straight lines, so it is no problem. What if the hallway has a bend in it? You could place a mirror at the bend to reflect the light beam around the corner. What if the hallway is very winding with multiple bends? You might line the walls with mirrors and angle the beam so that it bounces from side-to-side all along the hallway. This is exactly what happens in an optical fiber.

The light in a fiber-optic cable travels through the core (hallway) by constantly bouncing from the cladding (mirror-lined walls), a principle called total internal reflection. Because the cladding does not absorb any light from the core, the light wave can travel great distances.

However, some of the light signal degrades within the fiber, mostly due to impurities in the glass. The extent that the signal degrades depends on the purity of the glass and the wavelength of the transmitted light (for example, 850 nm = 60 to 75 percent/km; 1,300 nm = 50 to 60 percent/km; 1,550 nm is greater than 50 percent/km). Some premium optical fibers show much less signal degradation -- less than 10 percent/km at 1,550 nm.

1

3 0
3 years ago
A large fraction of the ultraviolet (UV) radiation coming from the sun is absorbed by the atmosphere. The main UV absorber in ou
irakobra [83]

Answer:

λ = 3.2 x 10⁻⁷ m = 320 nm

Explanation:

The relationship between the velocity of electromagnetic waves (UV rays) and the their frequency is:

v = fλ

where,

v = c = speed of the electromagnetic waves (UV rays) = speed of light

c = 3 x 10⁸ m/s

f = frequency of the electromagnetic waves (UV rays) = 9.38 x 10¹⁴ Hz

λ = wavelength of the electromagnetic waves (UV rays) = ?

Therefore, substituting the values in the relation, we get:

3 x 10⁸ m/s = (9.38 x 10¹⁴ Hz)(λ)

λ = (3 x 10⁸ m/s)/(9.38 x 10¹⁴ Hz)

<u>λ = 3.2 x 10⁻⁷ m = 320 nm</u>

So, the radiation of <u>320 nm</u> wavelength is absorbed by Ozone.

3 0
3 years ago
Read 2 more answers
ou are sitting in your car at rest at a traffic light with a bicyclist at rest next to you in the adjoining bicycle lane. As soo
madam [21]

Till the time car is just adjacent to the bicycle we can say

distance moved by cycle = distance moved by car

Time taken by car to accelerate from rest

t = \frac{v_f - v_i}{a}

t = \frac{49 - 0}{7} = 7 s

Time taken by cycle to accelerate

t = \frac{23 - 0}{15} = 1.53 s

now the distance moved by cycle in time "t"

d = \frac{23 + 0}{2}*1.53 + 23(t - 1.53)

distance moved by car in same time

d = \frac{7t + 0}{2}(t)

now make them equal

3.5t^2 = 17.595 - 35.19 + 23t

3.5 t^2 - 23t + 17.595 = 0

t = 5.68 s

so cycle will move ahead of car for t = 5.68 s

8 0
3 years ago
Read 2 more answers
Other questions:
  • Find the sine,cosine and tangent ratios​
    10·1 answer
  • Temperature is referred to as what Under the metric system
    5·1 answer
  • A 500kg elevator is raised to a height of 10 m in 10 seconds. Calculate the power of the motor.
    8·1 answer
  • What is one of the causes of daily variations in temperature on a planet’s surface?
    6·1 answer
  • What is the change in potential energy of the coil when it is rotated 180 ∘ so that its magnetic moment is parallel to the field
    10·1 answer
  • If you were on the open ocean on a large ship, what steps would you do to determine the height of a wave?
    14·1 answer
  • Regardless of their frequency, wavelength, or energy, all electromagnetic waves: A. travel only through the vacuum of space. B.
    5·1 answer
  • How often do the earth's magnetic poles switch?
    5·1 answer
  • Plz help, its an emergency, giving lots of points for it. and srry if its in the wrong subject, not really sure? I just don't un
    13·2 answers
  • Convert 5.6 bushels to hectoliters
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!