What are the common factors of 18 and 32
2 answers:
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Answer:
see explanation
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h. k) are the coordinates of the vertex and a is a multiplier
here (h, k) = (- 6, - 1), thus
y = a(x + 6)² - 1
To find a substitute one of the roots into the equation
Using (- 3, 0), then
0 = a(- 3 +6)² - 1
0 = 9a - 1 ( add 1 to both sides )
1 = 9a ( divide both sides by 9 )
a = , thus
y = (x + 6)² - 1 ← in vertex form
Expand factor and simplify
y = (x² + 12x + 36) - 1 ← distribute
y = x² +
x + 4 - 1
= x² +
x + 3 ← in standard form
You want to start by subtracting 5 from both sides to get 2/3x=-8/3 then cross multiply to get whole numbers which is 6=-24x then your gonna want to isolate the variable so divide both sides by -24 to get 6/-24=x then you can simplify to x=-1/4
